1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shkiper50 [21]
2 years ago
7

Investigar la función de los espejos esféricos y como funciona, en el microscopio.

Physics
1 answer:
NikAS [45]2 years ago
4 0

Answer:

yea

Explanation:

You might be interested in
The magnitude of the magnetic force on a current-carrying wire held in a magnetic
Kamila [148]

Answer:

All of the above

Explanation:

The magnitude of the magnetic force on a current-carrying wire held in a magnetic is given by the equation F = BIlsin \theta

Where B = Strength of the magnetic field

I = The current carried by the wire

l = length of the wire in the magnetic field

θ = Angle between the wire and the magnetic field

Based on the relationship written above, the magnitude of the magnetic force on the current - carrying wire in the magnetic field depends on the strength of the magnetic field (B), length of the wire(l), current in the wire (I).

All the options are correct.

3 0
3 years ago
Select the correct answer. Which of the following is a category of dance? O A. Group dance OB. Solo dance O C. Partner dance OD.
jeka57 [31]

Answer:

all of above I think sorry if I'm not right but I tried

3 0
2 years ago
Help me please and thank you
katovenus [111]

Answer:

go to : www.planetresourses.com/test2.00/answers, ant type in that test name

Explanation:

yee

3 0
3 years ago
What factors cause a rock to become metamorphic
Lynna [10]
Pressure and heat. I hope this helps
3 0
2 years ago
Read 2 more answers
A 26-kg sled is on a snow-covered slope. The coefficients of friction between the sled’s runners and the snow are µs = 0.096 and µ
sweet-ann [11.9K]

Answer:

Explanation:

Given

mass of sled =26 kg

coefficient of static friction \mu _s=0.096

coefficient of kinetic friction \mu _k=0.072

In order to move sled from rest we need to provide a force greater than static friction which is given by

f_s=\mu mg=0.096\times 26\times 9.8=24.46 N

After Moving Sled kinetic friction comes in to play which is less than static friction

f_k=\mu _kmg=0.072\times 26\times 9.8=18.34 N

therefore minimum force to keep moving sledge at constant velocity is 18.34 N

3 0
3 years ago
Other questions:
  • Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec
    5·1 answer
  • POINTS + BRAINLIEST TO CORRECT ANSWER
    8·1 answer
  • Suppose the Earth's magnetic field at the equator has magnitude 0.00005 T and a northerly direction at all points. How fast must
    10·1 answer
  • Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 21 degrees and 61 degree
    5·1 answer
  • Label the parts of a concave lens.
    5·2 answers
  • The place below earth's surface where the earthquake begins.
    10·1 answer
  • If the loop is removed from the field region in a time interval of 2.8 ms , find the average emf that will be induced in the wir
    9·1 answer
  • What acceleration does the force of earth's gravity peoduce
    13·1 answer
  • PLEASE HELP ME THIS IS VERY IMPORTANT!!!!!!!!!!!!! 20 points and I will give brainlyest
    6·2 answers
  • Running with an initial velocity of +11 m/s, a horse has an average acceleration of -1.8
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!