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Lilit [14]
3 years ago
9

Carbon-14 has a half-life of approximately 5,730 years. How many half-lives have occurred in a sample that contains 25 percent o

f the original amount of the parent isotope?
Chemistry
2 answers:
vagabundo [1.1K]3 years ago
4 0

Answer:

two half lives

Explanation:

half life is the time taken for the radioactivity of an isotope to reduce to half of its original value

therefore, in the first half life carbon-14 would have reduced by 50% in 5730 years

second half life, the isotope would have reduced to 25% in 11460 years

in three half lives, 12.5% of the isotope will be left after 17190 years, and so on .....

conclusively, 25% would remain after two half-lives have occurred

iogann1982 [59]3 years ago
3 0
If 25% is remaining, two half lives have occurred.

After one half life, 50% remains. The after a second, 25% remains

Hope this helps
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sergey [27]

Answer:

A voice echo

Your image in a mirror

Explanation:

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8 0
3 years ago
The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
BARSIC [14]
<h3>Answer:</h3>

              6.21 × 10²² Carbon Atoms

<h3>Solution:</h3>

Data Given:

                 Mass of Butane (C₄H₁₀)  =  1.50 g

                 M.Mass of Butane  =  58.1 g.mol⁻¹

Step 1: Calculate Moles of Butane as,

                 Moles  =  Mass ÷ M.Mass

Putting values,

                 Moles  =  1.50 g ÷ 58.1 g.mol⁻¹

                 Moles  =  0.0258 mol

Step 2: Calculate number of Butane Molecules;

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Butane Molecules can be written as,

            Moles  =  Number of C₄H₁₀ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Butane molecules,

             Number of C₄H₁₀ Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting value of moles,

     Number of C₄H₁₀ Molecules  =  0.0258 mol × 6.022 × 10²³ Molecules.mol⁻¹

                 Number of C₄H₁₀ Molecules  =  1.55 × 10²² C₄H₁₀ Molecules

Step 3: Calculate Number of Carbon Atoms:

As,

                            1 Molecule of C₄H₁₀ contains  =  4 Atoms of Carbon

So,

          1.55 × 10²² C₄H₁₀ Molecules will contain  =  X Atoms of Carbon

Solving for X,

 X =  (1.55 × 10²² C₄H₁₀ Molecules × 4 Atoms of Carbon) ÷ 1 Molecule of C₄H₁₀

X  =  6.21 × 10²² Atoms of Carbon

5 0
4 years ago
Read 2 more answers
Can somebody please help me asap !!!
EastWind [94]

Answer:

Option A. 1191.49 K

Explanation:

Data obtained from the question include:

The equation for the reaction is given below:

4HCl + O2 —> 2Cl2 + 2H2O

Enthalpy (H) = +280 KJ/mol = +280000 J/mol

Entropy (S) = +235 J/Kmol

Temperature (T) =..?

The temperature at which the reaction will be feasible can be obtained as follow:

Change in entropy (ΔS) = change in enthalphy (ΔH)/T

(ΔS) = (ΔH)/T

235 = 280000/T

Cross multiply

235 x T = 280000

Divide both side by 235

T = 280000/235

T = 1191.49 K

Therefore, the temperature at which the reaction will be feasible is 1191.49 K

4 0
4 years ago
Which cell organelle is where proteins are made? A. nucleus B. ribosome C. vacuole D. mitochondrion
N76 [4]

Answer:

B. ribosome

Explanation:

In the ribosomes, the codons get paired with anti codons to create a polypeptide or protein.

5 0
4 years ago
Read 2 more answers
You are given 100.0 ml of a 2.0 M solution of KOH. What would be the molarity of the solution if it is diluted to a volume of 10
Lostsunrise [7]

Answer:

0.2M

Explanation:

Data obtained from the question include:

C1 = 2.0 M

V1 = 100mL

V2 = 1000mL

C2 =?

Using the dilution formula C1V1 = C2V2, the molarity of the diluted solution can be obtained as follows:

C1V1 = C2V2

2 x 100 = C2 x 1000

Divide both side by the 1000

C2 = (2 x 100) / 1000

C2 = 0.2M

The molarity of the diluted solution is 0.2M

8 0
3 years ago
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