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mestny [16]
3 years ago
5

Robert has just bought a new model roket, and is trying to measure its flight characteristics. The rocket engine package claims

that it will maintain a constant thrust of 11.4 N until the engine is used up. Robert launches the rocket on a windless day, so that it travels straight up, and uses his laser range-finder to measure that the height of the rocket when the engine cuts off is 19.0 m. He also measures the rocket's peak height, which is 23.5 m. If the rocket has a mass of 0.613 kg, how much work is done by the drag force on the rocket during its ascent?
Physics
1 answer:
rewona [7]3 years ago
3 0
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh So Energy given to rocket = mgh Energy expended by engine = F x D (D= height where engine stops) Energy 'lost' to drag is the difference between the two values. please if this helped mark it as the brainiest answer.
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Boy pulls a 5.0-kg sled with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond. The boy pu
kykrilka [37]

Answer:

0.1

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velocity is constant , it means the net force is zero.

So, the component of force along the surface is equal to the friction force

FCosθ = friction force

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S GP A projectile of mass m moves to the right with a speed vi (Fig. P11.51a). The projectile strikes and sticks to the end of a
Andrews [41]

What is the kinetic energy of the system after the collision?

K_f=\frac{3}{2} \frac{m^{2}v_i^{2}  }{(M+3m)}

How this is calculated?

Given:

Initial speed=v_i

mass of rod=M

Let, Initial kinetic energy =K_i

Final kinetic energy=K_f

Moment of inertia =I

What is the moment of inertia?

I=(I_p)_0+(I_{rod})_0\\I=m(\frac{d}{2})^{2}  +\frac{Md^{2} }{12} \\I=\frac{(M+3m)d^{2} }{12}

What is the angular momentum?

By conservation of angular momentum,

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We know that, the final kinetic energy is given by,

K_f=I\omega^{2}\\K_f=\frac{1}{2} *\frac{(M+3m)d^{2} }{12} *\frac{36m^{2}v_i^{2}}{d^{2}(M+3m)^{2}}\\ K_f=\frac{3}{2} \frac{m^{2}v_i^{2}  }{(M+3m)}

What is the kinetic energy?

  • In physics, the kinetic energy of an object is the energy that it possesses due to its motion.
  • It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
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To know more about kinetic energy, refer:

brainly.com/question/114210

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