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mestny [16]
4 years ago
5

Robert has just bought a new model roket, and is trying to measure its flight characteristics. The rocket engine package claims

that it will maintain a constant thrust of 11.4 N until the engine is used up. Robert launches the rocket on a windless day, so that it travels straight up, and uses his laser range-finder to measure that the height of the rocket when the engine cuts off is 19.0 m. He also measures the rocket's peak height, which is 23.5 m. If the rocket has a mass of 0.613 kg, how much work is done by the drag force on the rocket during its ascent?
Physics
1 answer:
rewona [7]4 years ago
3 0
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh So Energy given to rocket = mgh Energy expended by engine = F x D (D= height where engine stops) Energy 'lost' to drag is the difference between the two values. please if this helped mark it as the brainiest answer.
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CaHeK987 [17]

Answer:

Explanation:

3 meters

4 0
2 years ago
I need to find 1).a,b,c
Aleksandr [31]
Let's cut through the weeds and the trash
and get down to the real situation:

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                  Ignore air resistance.


Gravity slows down the speed of any rising object by  9.8 m/s every second.
So the stone (aka Billy-Bob-Joe) continues to rise for

                     (5.89 m/s / 9.8 m/s²)  =  0.6 seconds.

At that timer, he has run out of upward gas.  He is at the top
of his rise, he stops rising, and begins to fall.

His average speed on the way up is  (1/2) (5.89 + 0) = 2.945 m/s .

Moving for 0.6 seconds at an average speed of  2.945 m/s,
he topped out at

                    (2.945 m/s) (0.6 s) =  1.767 meters above the trampoline.

With no other forces other than gravity acting on him, it takes him
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5 0
4 years ago
Suppose you are on a cart, initially at rest, which rides on a frictionless horizontal track. You throw a ball at a vertical sur
Len [333]

Answer:

F_c t_ c = -F_b t_b

And the forces are equal but in the opposite direction. So then we can write by general rule:

m_c \Delta V_{c} = -m_b \Delta V_b

Or equivalently:

m_c \Delta V_{c} +m_b \Delta V_b =0

Where: V_c represent the speed of the car and V_b the speed of the ball

m_c represent the mass of the car

m_b represent the mass of the ball

Since the ball is moving to the left and we assume that the total momentum not changes then the car need to move to the right in order to satisfy the equation and satisfy the balance.

By conservation of the momentum the car will move to the right since the ball is moves to the left.

So then the correct option for this case is :

A.Yes, and it moves to the right.

Explanation:

If we assume that we have the situation in the figure attached.

For this case we assume that the momentum changes are equal in magnitude and opposite in direction, so then we satisfy this:

F_c t_ c = -F_b t_b

And the forces are equal but in the opposite direction. So then we can write by general rule:

m_c \Delta V_{c} = -m_b \Delta V_b

Or equivalently:

m_c \Delta V_{c} +m_b \Delta V_b =0

Where: V_c represent the speed of the car and V_b the speed of the ball

m_c represent the mass of the car

m_b represent the mass of the ball

Since the ball is moving to the left and we assume that the total momentum not changes then the car need to move to the right in order to satisfy the equation and satisfy the balance.

By conservation of the momentum the car will move to the right since the ball is moves to the left.

So then the correct option for this case is :

A.Yes, and it moves to the right.

3 0
3 years ago
How much force is applied if a 130kg mass is accelerated at 5 m/s^2?​
STALIN [3.7K]

Answer:

650N

Explanation:

f= ma

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5 0
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3. Applying Concepts Explain why a canoe that has hollow, water-
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Answer:

I may be wrong

Explanation:

it it won't collapse because it is like a log logs don't sink when they are in water

5 0
3 years ago
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