force times gravity (FG) =mass times gravity (mg)
First you get a tool and remove some of the warping from the tip.hehe. Then you neatly wrap the wires around the nail. Wrap more if you want to make it stronger. Make sure your able to fit the battery. connect the end of the wire to the positive side. Be careful.
Answer:
![KE=3.529\times10^{−27}\ J](https://tex.z-dn.net/?f=KE%3D3.529%5Ctimes10%5E%7B%E2%88%9227%7D%5C%20J)
Explanation:
Given that
Wavelength λ=192 nm
So energy of photon,E
![E=\dfrac{hC}{\lambda }](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BhC%7D%7B%5Clambda%20%7D)
Now by putting the values
![h=6.6\times 10^{-34}\ m^2.kg/s](https://tex.z-dn.net/?f=h%3D6.6%5Ctimes%2010%5E%7B-34%7D%5C%20m%5E2.kg%2Fs)
![C=3\times 10^{8}\ m/s](https://tex.z-dn.net/?f=C%3D3%5Ctimes%2010%5E%7B8%7D%5C%20m%2Fs)
![E=\dfrac{6.6\times 10^{-34}\times 3\times 10^{8}}{192\times 10^{-9} }](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B6.6%5Ctimes%2010%5E%7B-34%7D%5Ctimes%203%5Ctimes%2010%5E%7B8%7D%7D%7B192%5Ctimes%2010%5E%7B-9%7D%20%7D)
![E=1.03\times 10^{-18} J](https://tex.z-dn.net/?f=E%3D1.03%5Ctimes%2010%5E%7B-18%7D%20J)
We know that
Kinetic energy given as
![KE=\dfrac{P^2}{2m}](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7BP%5E2%7D%7B2m%7D)
![KE=\dfrac{E^2}{2mC^2}](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7BE%5E2%7D%7B2mC%5E2%7D)
![KE=\dfrac{(1.03\times 10^{-18})^2}{2\times 1.67\times 10^{-27}(3\times 10^8)^2}](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B%281.03%5Ctimes%2010%5E%7B-18%7D%29%5E2%7D%7B2%5Ctimes%201.67%5Ctimes%2010%5E%7B-27%7D%283%5Ctimes%2010%5E8%29%5E2%7D)
![KE=3.529\times10^{−27}\ J](https://tex.z-dn.net/?f=KE%3D3.529%5Ctimes10%5E%7B%E2%88%9227%7D%5C%20J)
To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as
![\Delta P = F\Delta t](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20F%5CDelta%20t)
F = Force
![\Delta t = Time](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20Time)
At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as
![P = m \Delta v](https://tex.z-dn.net/?f=P%20%3D%20m%20%5CDelta%20v)
Where
m = Mass
Change in velocity
Our values are given as
![\Delta t=1.65s](https://tex.z-dn.net/?f=%5CDelta%20t%3D1.65s)
By equating the two equations we can find the Force,
![F\Delta t = m\Delta v](https://tex.z-dn.net/?f=F%5CDelta%20t%20%3D%20m%5CDelta%20v)
![F = \frac{m\Delta v}{\Delta t}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bm%5CDelta%20v%7D%7B%5CDelta%20t%7D)
![F = \frac{62(1.1-5.5)}{1.65}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B62%281.1-5.5%29%7D%7B1.65%7D)
Therefore, the net average force will be:
![F = - 165N](https://tex.z-dn.net/?f=F%20%3D%20-%20165N)
The negative symbol indicates that the direction of the force is upwards.