A 20.5 kg ball moving at 38.5 m/s on a horizontal, frictionless surface runs into a light spring of force
1 answer:
Answer:
7.68 m
Explanation:
Kinetic energy in ball = elastic energy in spring
KE = EE
½ mv² = ½ kx²
mv² = kx²
x = v √(m / k)
x = (38.5 m/s) √(20.5 kg / 515 N/m)
x = 7.68 m
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