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adoni [48]
3 years ago
15

Two moons orbit a planet in nearly circular orbits. Moon A has orbital radius r, and moon B has orbital radius 4r. Moon A takes

20 days to complete one orbit. How long does it take moon B to complete an orbit?
Physics
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

160 days

Explanation:

Using the equation

rA^3/TA^2 = rB^3/TB^2

Where rA is radius of Moon A = R

TA is Time for moon A complete one orbit = 20 days

rB is radius of Moon B =4R

TB is Time for moon B complete one orbit = ?

Therefore

rA^3/TA^2 = rB^3/TB^2

R^3/20^2 = (4R)^3/TB^2

Cross multiply to solve for TB, then we have

TB^2 × R^3 = (4R)^3 × 20^2

TB^2 × R^3 = 64 × R^3 × 400

TB^2 × R^3 = 25600 × R^3

Divide both sides by R^3

TB^2 = 25600

Square root both sides

TB = sqrt 25600

TB = 160days

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Newton’s Second Law of Motion.
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Determine the launch speed of a horizontally launched cannonball that lands 26.3
nlexa [21]

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u\sqrt{\frac{2H}{g} }

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/s^{2}.

So that:

26.3 = u\sqrt{\frac{2*19.3}{9.8} }

(26.3)^{2} = u^{2} x \frac{38.6}{9.8}

691.69 =  u^{2} x \frac{38.6}{9.8}

u^{2} = \frac{691.69*9.8}{38.6}

   = \frac{6778.562}{38.6}

u^{2} = 175.6104

⇒ u = \sqrt{175.6104}

  = 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.

4 0
3 years ago
What is the best description of the destructive interference of light?
Helga [31]

Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is cancelled exactly by a negative displacement of the other wave.

Answer:

The crest of one wave overlaps the trough of another.

8 0
3 years ago
Read 2 more answers
The balls velocity started at 20m/s and increased to 40 m/s in 3 seconds. What was the
Gnoma [55]

Answer:

a =  \frac{20}{3}  \frac{m}{s {}^{2} }

Explanation:

The formula for velocity is:

v = vo - a \times t

Where

vo

is the ball's initial velocity.

solving for a:

40 = 20  +    a \times t \\ 20 =   a \times t \\ 20 = 3a \\ a =  \frac{20}{3}

6 0
3 years ago
An asteroid exerts a 360-N gravitational force on a nearby spacecraft. If the spacecraft moves to a position three times as far
KIM [24]

Answer:

40 N

Explanation:

The gravitational force between the asteroid and the spaceship is given by:

F=G\frac{mM}{R^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M is the mass of the asteroid

m is the mass of the spaceship

R is the distance between the asteroid and the spaceship

The initial force is equal to:

F=G\frac{mM}{R^2}=360 N

Later, the spaceship moves to a position 3 times as far from the center of the asteroid, so R' = 3R. Therefore, the new force will be

F'=G\frac{mM}{R'^2}=G\frac{mM}{(3R)^2}=G\frac{mM}{9R^2}=\frac{1}{9}F

so, the force is decreased by a factor 9. Since the initial force was F=360 N, the new force will be

F'=\frac{360 N}{9}=40 N

3 0
4 years ago
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