Answer:
Step-by-step explanation:
11 t= -5 17 r = 27
12 n= -1 18 k = -20
13 m=-5
14 x= - 11
15 y = 70
16 f = - 70
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
He drove 111 miles
If we were given the distance Lan drove last weekend instead off how much gas he used then we would have to find the amount of gas used by lan.
Step-by-step explanation:
Ian's car can go 185 miles on 5 gallons of gas
On 5 gallons of gas lan's car can go 185 miles
Therefore in gallon of gas lan 's car can go
185/5 = 37
So, for 3 gallons of gas lan's car can go
3 × 37 = 111
for 3 gallons of gas lan's car can go 111 miles
If we were given the distance Lan drove last weekend instead off how much gas he used then we would have to find the amount of gas used by lan.
