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3 years ago

Define s.i unit of force explanation

Physics

1 answer:

kvv77 [185]3 years ago

3 0

<h3>Answer :</h3>

◈ As per newton's second law of motion, Force is defined as the product of mass and acceleration $.$

Mathematically,

$\dag\:\boxed{\bf{\purple{F=ma}}}$

Unit of mass : kg

Unit of acceleration : m/s²

Therefore,

Unit of force ➠ kg m/s²

SI unit : N (newton) or kg m/s²

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There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much

PIT_PIT [208]

P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

Note, you can get the power equation from:
P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.

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3 years ago

What force must the worker exert to get the box moving & what force must the worker exert to accelerate the box at 0.1 meter

photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

$F - F_k = m*a$

here

$F_k = kinetic friction = 220 N$

$m = mass = 500 kg$

$a = acceleration = 0.1 m/s^2$

now we will have

$F - 220 = 500* 0.1$

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3 0

3 years ago

What Law and explain why. An airplane turns on its jets to accelerate down a runway.

Kaylis [27]

Answer:Newton's 2nd law

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2 years ago

A car’s brakes decelerate it at a rate of -1.70 m/s2. What is the time, in seconds, required to slow the car from 15 m/s to 9.0

jeka94

Answer:

t = 3.52 s

Explanation:

Given that,

The deceleration of a car is, a = -1.7 m/s²

The initial velocity of the car, u = 15 m/s

Final velocity of the car, v = 9 m/s

We need to find the time that is required to slow the car from 15 m/s to 9 m/s. The definition of acceleration is :

$a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{9-15}{-1.7}\\\\t=3.52\ s$

So, it will take 3.52 seconds to slow the car from 15 m/s to 9 m/s.

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2 years ago

What is the potential energy, if a body of mass 250 kg is at a height of 30 metre?

stepan [7]

PE = (250) (30) (9.81) = 73575J
I used to use 9.81 as acceleration due to gravity. The answer might be different from what you expect

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3 years ago