Answer:
Explanation:
Given that,
Weight of jet
W = 2.25 × 10^6 N
It is at rest on the run way.
Two rear wheels are 16m behind the front wheel
Center of gravity of plane 10.6m behind the front wheel
A. Normal force entered on the ground by front wheel.
Taking moment about the the about the real wheel.
Check attachment for better understanding
So,
Clock wise moment = anti-clockwise moment
W × 5.4 = N × 16
2.25 × 10^6 × 5.4 = 16•N
N = 2.25 × 10^6 × 5.4 / 16
N = 7.594 × 10^5 N
B. Normal force on each of the rear two wheels.
Using the second principle of equilibrium body.
Let the rear wheel normal be Nr and note, the are two real wheels, then, there will be two normal forces
ΣFy = 0
Nr + Nr + N — W = 0
2•Nr = W—N
2•Nr = 2.25 × 10^6 — 7.594 × 10^5
2•Nr = 1.491 × 10^6
Nr = 1.491 × 10^6 / 2
Nr = 7.453 × 10^5 N
Answer:
All steps are 20 * 100 (break the rest into appropriate pieces)
You can multiply as follows
(2000) * ((3 * 60) + (2 * 60) + 60)
V = 2000 * 6 * 60) = 720,000 cm^3 = .72 m^3
.72 m^3 * 2400 kg / m^3 = 1728 kg
Answer:it helps get everyone in the same page
Explanation:
This is important so everyone knows what they should be doing
Answer:
Explanation:
The trick is in finding the volume.
Final Volume = 26.64
Initial Volume=<u>20.92</u> Subtract
Metal Volume 5.72 cm^3
Density = mass / volume
Density = 72.17 / 5.72
Density = 12.617
Answer:
Pressure is equal to the ratio of thrust to the area in contact. Upthrust is a force exerted by the fluids on an object placed in the fluid . Upthrust acts in upward direction.