What does it mean by that "length of an object is m"

Chuck and Jackie stand on separate carts, both of which can slide without friction. The combined mass of Chuck and his car, mcar

Ivenika [448]

Explanation:

a.)

We find the relative speed

u = vb + vc

b.)

chuck and the cart are at a rest position

mcartvc = mballvb

from part a above,

vc = u - vb

mcartu = vb(mcart + mball)

make vb the subject of the equation

$vb=\frac{mcartu}{mcart +mball}$

c.)

from anser a,

vb = u - vc

then mcart vc = mball(u-vc)

$vc= \frac{Mballu}{Mcart+Mball}$

d.

Mballvb = (Mcart + Mball)vj

we make vj the subject to get her relative speed

$vj=\frac{MballVb}{Mcart+Mball}$

e.

given the solution in part d above,

we have

$vj=\frac{MballVb}{Mcart+Mball}$

remember,

vb = u - vc

such that

$Vj = \frac{Mball(u-v)}{Mball +Mcart}$

thank you!

4 0

3 years ago

Which simple machine is NOT correctly matched with an appropriate task for its use?

Tcecarenko [31]

The simple machine that is not correctly matched with its appropriate task is the inclined plane because there is no such big ramp that is as high as 1 storey building, the appropriate task would be Lifting a heavy box and moving it across a room. and for the pulley : Moving a heavy box up to the second floor of a building.

6 0

3 years ago

(a) What is the potential between two points situated 10 cm and 20 cm from a 3.0-μC point charge? (b) To what location should th

julia-pushkina [17]

Answer:

(a) 135 kV

(b) The charge chould be moved to infinity

Explanation:

(a)

The potential at a distance of r from a point charge, Q, is given by

$V = -\dfrac{kQ}{r}$

where $k = 9\times 10^9 \text{ F/m}$

Difference in potential between the points is

$kQ\left[-\dfrac{1}{0.2\text{ m}} -\left( -\dfrac{1}{0.1\text{ m}}\right)\right] = \dfrac{kQ}{0.2\text{ m}} = \dfrac{9\times10^9\text{ F/m}\times3\times10^{-6}\text{ C}}{0.2\text{ m}}$