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natima [27]
3 years ago
10

Two particles are moving with positions given by x= 4t^2−2t and x= 6t^3+8t respectively.

Physics
1 answer:
Evgen [1.6K]3 years ago
6 0

Explanation:

<em>a)Which of the two has uniform acceleration?</em>

Acceleration is the second derivative of position.  The acceleration of the first particle is:

x = 4t² − 2t

v = 8t − 2

a = 8

The acceleration of the second particle is:

x = 6t³ + 8t

v = 18t² + 8

a = 36t

The first particle has uniform acceleration.

<em>b)Which one is likely to come to rest at some time during its motion?</em>

The particles come to rest when v = 0.  The first particle's velocity has a real zero at t = 4.  The second particle's velocity has only imaginary zeros, meaning v is never 0.

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2 years ago
A metal sphere of radius 2.0 cm carries an excess charge of 3.0 μC. What is the electric field 6.0 cm from the center of the sph
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Answer:

The electric field is  E = 7.5 *10^{6} \ N/C

Explanation:

From the question we are told that

    The radius of the metal sphere is  R = 2.0 \ cm  =  0.02 \ m

     The excess charge which the metal sphere carries is  q =  3.0 \mu C  =  3.0*10^{-6} \ C

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Generally the electric field is mathematically represented as  

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substituting values

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      E = 7.5 *10^{6} \ N/C

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