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natima [27]
3 years ago
10

Two particles are moving with positions given by x= 4t^2−2t and x= 6t^3+8t respectively.

Physics
1 answer:
Evgen [1.6K]3 years ago
6 0

Explanation:

<em>a)Which of the two has uniform acceleration?</em>

Acceleration is the second derivative of position.  The acceleration of the first particle is:

x = 4t² − 2t

v = 8t − 2

a = 8

The acceleration of the second particle is:

x = 6t³ + 8t

v = 18t² + 8

a = 36t

The first particle has uniform acceleration.

<em>b)Which one is likely to come to rest at some time during its motion?</em>

The particles come to rest when v = 0.  The first particle's velocity has a real zero at t = 4.  The second particle's velocity has only imaginary zeros, meaning v is never 0.

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A tennis player tosses a tennis ball straight up and then catches it after 2.07 s at the same height as the point of release.
prisoha [69]

(a) The ball will accelerate at a speed of 9.81 m/s² while it is in flight.

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(d) It will reach a maximum height of 21.0 m.

<h3 /><h3>What is speed?</h3>

Speed is defined as the change in distance with regard to time. A scalar quantity, speed. It is a temporal element, m/sec is its unit.

The information provided in the issue is;

u is the fall's beginning speed in m/sec;

h is the fall's distance

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a. The ball's speed while in flight is equal to the acceleration caused by gravity, which is 9.81 m/s².

b. When the ball reaches its highest point, its velocity will be zero.

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d. The formula is used to determine the highest height it can reach.

\rm u^2 = - 2gh \\\\ (20.30)^2 = -2 \times (-9.8) \times h \\\\ 412.09  = 19.6 \times h\\\\ h = 412.09/19.6\\\\ h = 21.00 m

As a result, the ball's greatest height, beginning velocity, and acceleration are all 9.81 meters per second, zero meters per second, 20.30 meters per second, and 21 meters accordingly.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

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