Answer:
The average drag force is 1.206 (-i) N
Explanation:
You have to apply the equations of<em> Impulse</em>:
I=FmedΔt
Where I and Fmed (the average force) are vectors.
The Impulse can also be expressed as the change in the <em>quantity of motion</em> (vector P)
I=P2-P1
P=mV (m is the mass and v is the velocity)
You can calculate the quantity of motion at the beggining and at the end of the given time:
Replace the mass in kg, dividing the mass by 1000 to convert it from g to kg.
P1=(0.179kg)(30.252m/s) i= 5.414 i kg.m/s
P2=0.179kg)(28.452m/s) i = 5.092 i kg. m/s
Where i is the unit vector in the x-direction.
Therefore:
I= 5.092 i - 5.414 i = -0.322 i
The average drag force is:
Fmed= I/Δt = -0.322 i/ 0.267s = -1.206 i N
False.
Unweathered rock that underlies soul is known as bedrock.
Kinetic energy = (1/2) (mass) (speed squared)
Kinetic energy = (1/2) (400 kg) (17 m/s)²
Kinetic energy = (1/2) (400 kg) (289 m²/s²)
<em>Kinetic energy = 57,800 Joules</em>
<em></em>
(That's some amazing house. I'd like to be there to see it.)
Answer:
Partial Pressure of F₂ = 1.30 atm
Partial pressure of Cl₂ = 0.70 atm
Explanation:
Partial pressure for gases are given by Daltons law.
Total pressure of a gas mixture = sum of the partial pressures of individual gases
Pt = P(f₂) + P(cl₂)
Partial pressure = mole fraction × total pressure
Let the mass of each gas present be m
Number of moles of F₂ = m/38 (molar mass of fluorine = 38 g/Lol
Number of moles of Cl₂ = m/71 (molar mass of Cl₂)
Mole fraction of F₂ = (m/38)/((m/38) + (m/71)) = 0.65
Mole fraction of Cl₂ = (m/71)/((m/38) + (m/71)) = 0.35 or just 1 - 0.65 = 0.35
Partial Pressure of F₂ = 0.65 × 2 = 1.30 atm
Partial pressure of Cl₂ = 0.35 × 2 = 0.70 atm
<span>The
kinetic energy is the work done by the object due to its motion. It is
represented by the formula of the half the velocity squared multiply by the
mass of the object. In this problem, you have two vehicles, the other one is large and the
other one is small. Let us assume that they travel with the same velocity. Note
that the kinetic energy is proportional to the mass of the object. So when you
increase the mass of the other, it also increases the kinetic energy of that
object. The same holds true for the two vehicles. The larger the vehicle, its
kinetic energy is also large and therefore its stopping distance will be longer
than that of the smaller vehicle.</span>
