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tensa zangetsu [6.8K]
3 years ago
9

What type of simple machine is an electric fan?

Physics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

An electric fan is considered to be a mixture of several simple machines. It includes the Wheel and Axle type, wedges, and the Inclined plane types. The blades of an electric fan are the inclined planes and the wedges.

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If kinetic energy of a body of mass 10 kg is 2000 J find velocity ​
weqwewe [10]

Answer:

I guess answer is 10m/s.

Explanation:

Kinetic Energy=1/2 mv^2

or,2000J=1/2×10kg×v^2

or2000J=5kg.v^2

or,2000J/5kg=v^2

or,100J/kg=v^2

or,v=10m/s

6 0
2 years ago
A charged particle is accelerated in a uniform electric field. When its velocity is 2 m/s, its electric potential energy is 100
zavuch27 [327]

Answer:

particle's potential energy = 70J

Explanation:

From conservation of energy; K1 + Ue1 = K2 + Ue2

where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.

k1 = 10J, Ue1 = 100J

K2 = 40J

substitute into K1 + Ue1 = K2 + Ue2

Ue2 = K1 + Ue1 - K2

= 10 +100 - 40

Ue2 = 70J

7 0
3 years ago
Calculate the work function that requires a 475 nm photon to eject an electron of 1.25 eV.
lapo4ka [179]
The work function has the formula
E = h v

where
E is the energy
h is the constant
v is the frequency

Since the given is wavelength, we use the relationship between frequency and wavelength
v = c / λ
where
c is the speed of light
<span>λ is the wavelength
</span>
So.
E = h c / <span>λ
h = E</span><span>λ / c = 1.25 eV (475x10-9m) / (3x10^8 m/s)
h = 1.9792 x 10^-15

The work function is:
E = 1.9792 x 10-15 v

</span>
3 0
3 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
4 years ago
Can someone help me please? I am stuck.
Mars2501 [29]

The distance traveled and the time it takes to travel are both going up at a steady rate. The distance goes from lap 1, lap 2, lap 3, lap 4. The time is increasing by a minute each time. When both the x and y scenario are increasing at a STEADY RATE the line will be linear. B displays a linear line.

8 0
4 years ago
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