Answer: Newton
Explanation:-
Force is defined as an interaction that causes an affected object to be pushed or pulled in a certain direction.
where m= mass of an object
a = acceleration of the object
S.I unit of mass is kg and S.I units of acceleration is 
Thus For S,I units of force:
Answer:
Velocity is the displacement (change In position of an an object it is similar to distance ) divided by the time taken. SI unit m/s (metre per second)
60.3° from due south and 5.89 m/s For this problem, first calculate a translation that will put John's destination directly on the origin and apply that translation to Mary's destination. Then the vector from the origin to Mary's new destination will be the relative vector of Mary as compared to John. So John is traveling due south at 6.7 m/s. After 1 second, he will be at coordinates (0,-6.7). The translation will be (0,6.7) Mary is traveling 28° West of due south. So her location after 1 second will be (-sin(28)*10.9, -cos(28)*10.9) = (-5.117240034, -9.624128762) After translating that coordinate up by 6.7, you get (-5.117240034, -2.924128762) The tangent of the angle will be 2.924128762/5.117240034 = 0.57142693 The arc tangent is atan(0.57142693) = 29.74481039° Subtract that value from 90 since you want the complement of the angle which is now 60.25518961° So Mary is traveling 60.3° relative to due south as seen from John's point of view. The magnitude of her relative speed is sqrt(-5.117240034^2 + -2.924128762^2) = 5.893783 m/s Rounding the results to 3 significant digits results in 60.3° and 5.89 m/s
Answer:
![\phi=1.55 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D1.55%20%5BeV%5D)
Explanation:
We can use the work function equation for a photoelectric experiment:
- h is the plank constant
- c is the speed of light
- λ is the wave length
- K is the kinetic energy (or K=eΔV)
So we will have:
![\phi=3.64*10^{-19}[J]-0.728 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D3.64%2A10%5E%7B-19%7D%5BJ%5D-0.728%20%5BeV%5D)
![\phi=(3.64*10^{-19}[J]*\frac{1eV}{1.6*10^{-19}[J]})-0.728 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D%283.64%2A10%5E%7B-19%7D%5BJ%5D%2A%5Cfrac%7B1eV%7D%7B1.6%2A10%5E%7B-19%7D%5BJ%5D%7D%29-0.728%20%5BeV%5D)
![\phi=2.28 [eV] - 0.728 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D2.28%20%5BeV%5D%20-%200.728%20%5BeV%5D)
I hope it helps you!
Answer:
H = 6.93 m
Explanation:
given data
velocity v = 35 m/s
horizontal component Vx = 33 m/s
solution
we get here maximum height so first we get vertical component here that is express as
Vy = 
.........................1
put here value
Vy = 
Vy = 11.66 m/s
and
now we get height
H = 
.............................2
put here value
H = 
H = 6.93 m
