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kvv77 [185]
3 years ago
15

Can I have some help please

Chemistry
1 answer:
KonstantinChe [14]3 years ago
6 0
He can help you via watzapp
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How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2
NNADVOKAT [17]

Answer:

17 g Ba(NO₂)₂

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

4.5 × 10²² molecules Ba(NO₂)₂

<u>Step 2: Define conversion</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

<u>Step 3: Dimensional Analysis</u>

<u />4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )

= 17.1384 g Ba(NO₂)₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

7 0
3 years ago
How many oxygen atoms are contained in the following chemical formula? 2agno3
sesenic [268]

It would be: 2*3 = 6 oxygen atoms

OPTION D IS YOUR ANSWER......

7 0
4 years ago
Which type of electromagnetic radiation has a longer wavelength than visible light?
Feliz [49]
Infrared radiation if i’m correct
5 0
3 years ago
Read 2 more answers
Locate the ion that has no change in oxidation number in redox reactions.
natali 33 [55]

a. Spectator ions are the ones that are present but does not enter into the actual chemical  reaction.

b. Na⁺ and NO₃⁻ ions are spectator ions involved in this above mentioned reaction

<u>Explanation:</u>

  • In redox reactions, for example reaction of aqueous silver nitrate and aqueous sodium chloride, silver chloride settles down as a precipitate by the addition of Ag⁺ ion from AgNO₃ and Cl⁻ ions from NaCl .
  • The other 2 ions that is NO₃⁻ ion and Na⁺ ion in the reaction do not enter into the reaction and they are called as Spectator ions.

This can be expressed as the following equation,

AgNO₃(aq) + NaCl(aq) →AgCl(s) + NaNO₃

5 0
4 years ago
How many moles of NaCl are needed to make 5.25 L of a 0.25 M solution
zhenek [66]

Answer:

m = 21.915 g of NaC to create the right balance between

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