Answer:
Oxide sugar dissolved in water pond
because water + sugar= sugar melts but the oxide purifys the water.
Explanation:
<u><em>#carryonlearning!</em></u>
Answer:
Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the
temperature of the water. The water in the beaker began to boil when it reached the temperature of
100'C. If Mario completes the same experiment with 25mL of water, what would happen to the boiling
point?
a) The water will not reach a boil.
b) The boiling point of water will increase.
c) The boiling point of water will decrease.
d) The boiling point of water will stay the same.
Explanation:
Answer:
Na the valency electrons is 1
The ion charge is positive 1
K the valency electrons is 1
The ion charge is positive 1
Explanation:
Mg the valency electron is 2 The ion charge is positive 2
Ca the valency electron is 2 The ion charge is positive 2
Al the valency electron is 3 The ion charge is positive 3
O the valency electron is 2 The ion charge
is negative 2
F the valency electron is 1 The ion charge is negative 1
Cl the valency electron is 1 The ion charge
is negative 1
N the valency electron is 3 The ion charge is negative 3
S the valency electron is 2 The ion charge is
negative 2
The answer is <span>C. The mixture is made up of different consistencies.
The main difference between a heterogeneous and a homogeneous mixture is that the heterogeneous mixture is </span><span>made up of different consistencies that are not evenly mixed throughout. For example, the homogeneous mixture is milk while milk with cereals is the heterogeneous mixture.</span>
<h3>
Answer:</h3>
5.6 L
<h3>
Explanation:</h3>
We are given;
- Initial volume, V1 = 3.5 L
- Initial pressure, P1 = 0.8 atm
- Final pressure, P2 = 0.5 atm
We are required to calculate the final volume;
- According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.
- That is; P α 1/V
- Mathematically, P=k/V
- At two different pressure and volume;
P1V1 = P2V2
In this case;
Rearranging the formula;
V2 = P1V1 ÷ P2
= (0.8 atm × 3.5 L) ÷ 0.5 atm
= 5.6 L
Therefore, the resulting volume is 5.6 L
