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SSSSS [86.1K]
3 years ago
9

Explain why it is important to keep all variables that might affect the dependent variable, other than the manipulated variable

constant?
Physics
2 answers:
zlopas [31]3 years ago
7 0
So that when you see a result of an experiment or equation, you know WHICH variable caused it.
Inga [223]3 years ago
5 0
<span>You have multiple confounding variables, you cannot accurately conclude the relationship between the manipulated and dependent variable because the other variables that are not controlled for could be the reason for seeing a certain change</span>
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How often is carbon dioxide cycled through the atmosphere
olga55 [171]

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What are some possible examples of genetic characteristics that can be passed down to child??????
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8 0
3 years ago
Read 2 more answers
Harrison wanted to find out what soil works best for growing roses. He grew them in potting soil, clay, sand, and soil he found
zepelin [54]

Answer:

This question is asking to identify the following variables:

Independent variable (IV): TYPE OF SOIL

Dependent variable (DV): HEIGHT AND NUMBER OF LEAVES

Control group: None in this experiment

Constant: SAME ROSE PLANT, SAME TIME INTERVAL (1 WEEK)

Explanation:

Independent variable in an experiment is the variable that is manipulated or changed by the experimenter in order to effect a measurable outcome. In this case, the independent variable is the TYPE OF SOIL used.

Dependent variable is the measurable variable that responds to changes made to the independent variable. In this experiment, the dependent variable is the HEIGHT AND NUMBER OF LEAVES of each rose.

Constants or control variable is the variable that is kept unchanged or constant for all groups throughout the experiment. In this experiment, the constants are SAME ROSE PLANT, SAME TIME INTERVAL (1 WEEK).

Control group are the groups that does not receive the experimental treatment. In this case, all the groups received the experimental treatment (different soil types). Hence, there is no control

4 0
3 years ago
A mass m = 14 kg is pulled along a horizontal floor with NO friction for a distance d =5.7 m. Then the mass is pulled up an incl
frosja888 [35]

Answer:

W ≅ 292.97 J

Explanation:

1)What is the work done by tension before the block goes up the incline? (On the horizontal surface.)

Workdone by the tension before the block goes up the incline on the horizontal surface can be calculated using the expression;

W = (Fcosθ)d

Given that:

Tension of the force = 62 N

angle of incline θ =  34°

distance d =5.7 m.

Then;

W = 62 × cos(34) × 5.7

W = 353.4 cos(34)

W = 353.4 × 0.8290

W = 292.9686 J

W ≅ 292.97 J

Hence,  the work done by tension before the block goes up the incline = 292.97 J

8 0
3 years ago
If a certain silver wire has a resistance of 3.00 Ï at 11.0°c, what resistance will it have at 25.0°c?
Romashka [77]
11.30      times the nuber of toys
7 0
3 years ago
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