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nikklg [1K]
3 years ago
9

A scientist finds a fossil that contains a long beak. He can assume which of the following things?

Chemistry
1 answer:
Lyrx [107]3 years ago
8 0
So lets look at the uses of a beak. what can a beak be used for? in today's animal kingdom beaked animals usually need to use that hard tool to dig into the ground, roots, and trees to find food. so the answer would be t<span>he animal most likely ate worms that lived under ground</span>
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(6.0 x 10^4) (3.1 x 10^1
myrzilka [38]

Answer would be,1.86 x 10^4 hopefully that help you ❤

5 0
3 years ago
What is the difference between a polar and a nonpolar bond?And how can i figure out if its polar or nonpolar in a bond question?
ra1l [238]

Answer:

If the electronegativity of two atoms is basically the same, a nonpolar covalent bond will form, and if the electronegativity is slightly different, a polar covalent bond will form.

Explanation:

that's your answer very easy.

5 0
3 years ago
Read 2 more answers
Natural gas burns in air to form carbon dioxide and water, releasing heat. CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔHrxn = -802.3 kJ.
Olenka [21]

Answer:

1) Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

Explanation:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g) ,\Delta H_{rxn} =-802.3 kJ

1) Minimum mass of  methane required to raise the temperature of water by 21.0°C.

Mass of water = m = 45.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 21.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 45.0 g\times 4.18 J/g^oC\times 21.0^oC

Q = 3,950.1 J = 3.9501 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 3.950.1 kJ of heat will be given by:

=\frac{3.950.1 kJ}{802.3 kJ}=0.004923 mol

Mass of 0.004923 moles of methane :

0.004923 mol × 16 g/mol=0.0788 g

Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of  methane required to raise the temperature of water by 26.0°C.

Mass of water = m = 50.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 26.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 50.0 g\times 4.18 J/g^oC\times 26.0^oC

Q = 5,434 J= 5.434 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 5.434 kJ of heat will be given by:

=\frac{5.434 kJ}{802.3 kJ}=0.006773 mol

Mass of 0.006773 moles of methane :

0.006773 mol × 16 g/mol= 0.108 g

Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

6 0
4 years ago
Mixture is a
yaroslaw [1]

Answer:

compund

Explanation:

i took the quiz

4 0
3 years ago
Write a balanced equation using the correct formulas and include conditions (s, l, g or aq) for each of the following reactions.
Aloiza [94]

Answer:

2Fe(s) + 3Cl2(g) → 2FeCl3(s)

Explanation:

Step 1: Data given

iron = Fe = solid = Fe(s)

chlorine = Cl2 = gas = Cl2(g)

iron(III) chloride = FeCl3 = solid = FeCl3(s)

Step 2: The unbalanced equation

Fe(s) + Cl2(g) → FeCl3(s)

Step 3: Balancing the equation

Fe(s) + Cl2(g) → FeCl3(s)

On the left we have 2x Cl (in Cl2) and on the right side we have 3x Cl (in FeCl3). To balance the amount of Cl we have to multiply Cl2 (on the left) by 3 and FeCl3 by 2.

Fe(s) + 3Cl2(g) → 2FeCl3(s)

On the left side we have 1x Fe and on the right side we have 2x Fe (in 2FeCl3). To balance the amount of Fe, we have to multiply Fe on the left side by 2. Now the equation is balanced.

2Fe(s) + 3Cl2(g) → 2FeCl3(s)

6 0
4 years ago
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