All categories

3 years ago

A scientist finds a fossil that contains a long beak. He can assume which of the following things?

1 answer:

8 0

So lets look at the uses of a beak. what can a beak be used for? in today's animal kingdom beaked animals usually need to use that hard tool to dig into the ground, roots, and trees to find food. so the answer would be t<span>he animal most likely ate worms that lived under ground</span>

You might be interested in

Which of the following statements is true about both nuclear fusion and nuclear fission?

creativ13 [48]

The correct answer is A.

B is incorrect because that only applies to nuclear fission.

C is incorrect because it only applies to nuclear fusion.

D is incorrect because energy can be neither created nor destroyed meaning that this statement is physically impossible,

8 0

3 years ago

Read 2 more answers

Science 6th grade please help me :)

Gnom [1K]

I’m pretty sure the answer is D :)

6 0

3 years ago

Read 2 more answers

The sun’s core is made of solid rock. True or false

KengaRu [80]

Answer:

False

Explanation:

Heres what its made of:

The core is made of hot, dense plasma (ions and electrons), at a pressure estimated at 265 billion bar (3.84 trillion psi or 26.5 petapascals (PPa)) at the center. Due to fusion, the composition of the solar plasma drops from 68–70% hydrogen by mass at the outer core, to 34% hydrogen at the core/Sun center.

8 0

3 years ago

Which of the following is a testable hypothesis

natka813 [3]

Answer:

Explanation:

8 0

3 years ago

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.

patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of $NH_{3}$ is as follows:.

$2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)$

And, initially only $NH_{3}$ is present.

The given data is as follows.

$P_{NH_{3}}$ = 2.3 atm at equilibrium

$P_{H_{2}} = 3 \times P_{N_{2}}$ = 0.69 atm

Therefore,

$P_{N_{2}} = \frac{0.69 atm}{3}$

= 0.23 aatm

So, $P_{NH_{3}}$ = 2.3 - 2(0.23)

= 1.84 atm

Now, expression for $K_{p}$ will be as follows.

$K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}$

$K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}$

= $\frac{0.23 \times 0.33}{3.39}$

= 0.0224

or, $K_{p} = 2.2 \times 10^{-2}$

Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is $2.2 \times 10^{-2}$ .

6 0

3 years ago