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Readme [11.4K]
3 years ago
10

Solve the system of equations displayed in the picture.

Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0

The answer is D) (-1,-12)

Reason:

1) substitute 2x-10 for y in y=4x-8

2) 2x-10=4x-8

3) -2x-10=-8

4) -2x=2

5) x=-1

6) substitute -1 for x in y=2x-10

7) y=(2)(-1)-10

8) y=-12

Answer

x=-1 and y=-12

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Drag the tiles to the boxes to form correct pairs.
FrozenT [24]

Answer:

1 .4x2-9= 2x+3,2x-3

2 .16x2-1=4x-1,4x+1

3 .16x2-4=4(2x+1)(2x-1)

4 .4x2-1=(2x+1)(2x-1)

Step-by-step explanation:

16x² − 1  = (4x − 1)(4x + 1) ;  16x² − 4  = 4(2x + 1)(2x − 1); 4x² − 1  = (2x + 1)(2x − 1) ;

4x² − 9 = (2x + 3)(2x − 3)

16x² − 1  is the difference of squares.  This is because 16x² is a perfect square, as is 1.  To find the factors of the difference of squares, take the square root of each square; one factor will be the sum of these and the other will be the difference.

The square root of 16x² is 4x and the square root of 1 is 1; this gives us (4x-1)(4x+1).

16x² − 4 is also the difference of squares.  The difference of 16x² is 4x and the square root of 4 is 2; this gives us (4x-2)(4x+2).  However, we can also factor a 2 out of each of these binomials; this gives us

2(2x-1)(2)(2x+1) = 2(2)(2x-1)(2x+1) = 4(2x-1)(2x+1)

4x² − 1  is also the difference of squares.  The square root of 4x² is 2x and the square root of 1 is 1; this gives us (2x-1)(2x+1).

4x² − 9 is also the difference of squares.  The square root of 4x² is 2x and the square root of 9 is 3; this gives us (2x-3)(2x+3).

3 0
3 years ago
REASONING An even integer can be represented by the expression $2n$ , where $n$ is any integer. Find three consecutive even inte
san4es73 [151]

Answer:

First Integer = 16

Second Integer = 18

Third integer = 20

Step-by-step explanation:

An even integer is represented by 2n

Where n is any integer

Let :

First Integer = 2n - 2

Second Integer = 2n

Third integer = 2n + 2

The sum of three even consecutive numbers = 2n - 2 + 2n + 2n + 2

= 2n + 2n + 2n - 2 + 2 = 54

= 6n = 54

n = 54/6

n = 9

First Integer = 2n - 2 = 2(9) - 2

= 16

Second Integer = 2n = 2(9)

= 18

Third integer = 2n + 2 = 2(9) + 2

= 20

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