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3 years ago

Solve the system of equations displayed in the picture.

Mathematics

1 answer:

bagirrra123 [75]3 years ago

7 0

The answer is D) (-1,-12)

Reason:

1) substitute 2x-10 for y in y=4x-8

2) 2x-10=4x-8

3) -2x-10=-8

4) -2x=2

5) x=-1

6) substitute -1 for x in y=2x-10

7) y=(2)(-1)-10

8) y=-12

Answer

x=-1 and y=-12

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2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

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3 years ago

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GuDViN [60]

Answer:

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Step-by-step explanatio

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2 years ago

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KatRina [158]

Answer:

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Step-by-step explanation:

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2 years ago

Two students, Carlos and Sophie, factored the trinomial -4x2 − 10x + 6. Sophie factored it as -2(2x − 1)(x + 3) and Carlos facto

damaskus [11]

Sophie has factored the term completely while Carlos has not factored the term completely.

Step-by-step explanation:

We need to factor the trinomial:

$-4x^2-10x + 6$

Factoring:

$-4x^2-10x + 6\\Taking\,\,-2\,\,common:\\-2(2x^2+5x-3)\\Now\,\,factoring:\\-2(2x^2+6x-x-3)\\-2(2x(x+3)-1(x+3))\\-2(2x-1)(x+3)$

So, the factored form of $-4x^2-10x + 6$ is $-2(2x-1)(x+3)$

So, Sophie has factored the term completely. The terms are factored when we cannot further simplify it. Since Carlos factored (x+3)(-4x+2) 2 can be taken common from the term (-4x+2) so, it is not factored completely.

Keywords: Factoring the terms

Learn more about Factoring the terms at:

#learnwithBrainly

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2 years ago