Answer:
2.8248 g
Explanation:
First, consider the balanced chemical equation:
Then we calculate the number of moles in 4.11 g of citric acid:
n(citric acid)=
According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.
so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol
mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol
= 2.8248 g
We need to know how many valence electrons are present in a given molecule in order to determine its Lewis dot structure.
<h3>
What is Lewis dot structure?</h3>
Lewis dot structure is defined as the visual representation of atoms' electrons using a diagram. It describe the bonds that exist between a molecule's lone pairs of electrons and its atoms.
A lone pair of electrons on the atom with the formal charge of 1- can typically be converted into a bonding pair that is shared with the atom that has the formal charge of 1+ in order to reduce the formal charges when they are present.
Thus, we need to know how many valence electrons are present in a given molecule in order to determine its Lewis dot structure.
To learn more about Lewis dot structure, refer to the link below:
brainly.com/question/20300458
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Answer:
6 moles
Explanation:
You have a 1:3 ratio between nitrogen gas and hydrogen gas
Answer:
A: 1,2-dimethylcyclopropane
Explanation:
The possible cyclic structure with formula C₅H₁₀ are shown in the image.
A is a cyclic compound. On monochlorination, A yields 3 products.
To have 3 products on monochlorination, there should be three different carbon atoms.
Considering structure 1, all carbons have same nature, thus only one product will be formed and thus not a structure of A.
Considering structure 2, there are two different carbon atoms, thus two different structure are formed and thus not a structure of A.
Considering structures 3 and 4 , there are four different carbon atoms, thus four products will be formed and either of them are not a structure of A.
Considering structure 5, there are three different carbon atoms, thus three different structure are formed and thus the A is structure 5.