No. Of hydrogen atoms is4
No. Of sulphur atoms is 2
No. Of oxygen atoms is 8
Explanation:
Let f₁ is the fundamental frequency, 
Lower pitch frequency, 
Fundamental frequency is,
.....(1)
Lower frequency is,
..............(2)
Dividing equation (1) and (2) as :




So, the ratio of linear mass density μ of the string with the higher pitch to that of the string with the lower pitch is 0.00132. Hence, this is the required solution.
Answer:
I think the answer is tempurature
Explanation:
Answer:
0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz
Explanation:
The fundamental frequency of a standing wave on a string is given by

where
L is the length of the string
T is the tension in the string
is the mass per unit length
For the string in the problem,
L = 30.0 m

T = 20.0 N
Substituting into the equation, we find the fundamental frequency:

The next frequencies (harmonics) are given by

with n being an integer number and f being the fundamental frequency.
So we get:



Answer:
100,048
Explanation:
K.E = 1/2 m (v)^2
K.E = 1^/2 * 74 * (52)^2
K.E = 100,048J =100.048kJ