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NemiM [27]
2 years ago
12

A simple pendulum of length 2.5 m makes 5.0 complete swings in 16 s. What is the acceleration of gravity at the location?

Physics
1 answer:
Norma-Jean [14]2 years ago
8 0
<h2>The acceleration of gravity at the location is 9.64 m/s²</h2>

Explanation:

Length of pendulum = 2.5 m

Time taken for 5 swings = 16 seconds

Time taken for 1 swing = 3.2 seconds

Period of pendulum = 3.2 seconds.

We have equation for period of simple pendulum as

             T=2\pi \sqrt{\frac{l}{g}}

Where l is the length of pendulum and g is acceleration due to gravity.

Substituting

                 T=2\pi \sqrt{\frac{l}{g}}\\\\3.2=2\pi \sqrt{\frac{2.5}{g}}\\\\g=\frac{4\pi^2 \times 2.5}{3.2^2}\\\\g=9.64m/s^2

The acceleration of gravity at the location is 9.64 m/s²

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An object of mass 25kg is falling from the height h=10 m. calculate
r-ruslan [8.4K]

Answer:

a=2500J,b=1000K,c=1000J,d=14.142m/s

Explanation:

V²=U²+2gh

V²=0 + 2×10×10=200m/s

a).kinetic energy=(1/2)mv²=(1/2)25×200=2500

potential energy=mgh

p.e=25×10×10=2500J

pe+ke=2500+2500=5KJ

b).mgh=25×10×4=1000J

c). V²=U²+2gh

V²=0+2×10×4

V²=80

kinetic energy=(1/2)mv²

=(1/2)25×80

=1KJ

d). From my first paragraph V²=200

V=√200

V=14.142m/s

6 0
3 years ago
6. A golf ball is hit a distance of 300 yards in 10 sec. What is the speed of the golf ballo
katen-ka-za [31]

The speed of the ball is 27.4 m/s

Explanation:

The speed of an object is given by:

speed=\frac{d}{t}

where

d is the distance covered

t is the time taken

In this problem, we have:

d = 300 yards is the distance covered by the golf ball

t = 10 s is the time taken

Keeping in mind that

1 yard = 0.914 m

We can convert the distance from yards to meters:

d = 300 \cdot 0.914 = 274.2 m

And substituting into the equation, we find the speed of the ball:

speed=\frac{274.2}{10}=27.4 m/s

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

3 0
2 years ago
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by
Vlad [161]

Answer: D. 5cm

Explanation:

Given the following :

Focal length (f) = - 6.0 cm

Height of object = 15.0cm

Distance of object from mirror (u) = 12.0cm

Height of image produced by the mirror =?

Firstly, we calculate the distance of the image from the mirror.

Using the mirror formula

1/f = 1/u + 1/v

1/v = 1/f - 1/u

1/v = 1/-6 - 1/12

1/v = - 1/6 - 1/12

1/v = (- 2 - 1) / 12

1/v = - 3 / 12

v = 12 / - 3

v = - 4

Using the relation :

(Image height / object height) = (- image distance / object distance)

Image height / 15 = - (-4) / 12

Image height / 15 = 4 / 12

Image height = (15 × 4) / 12

Image height = 60 / 12

Image height = 5cm

6 0
3 years ago
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