Answer:
8 (maybe 18)
Explanation:
Depends on whether you have the d orbitals. If not, it's 8, and it's 18 including the d orbitals
Answer:
t the battery of potential difference V be used to charge the capacitor of capacitance C.
∴ the charge stored in the capacitor q=CV
Now the battery is disconnected, so the the charge of the capacitor becomes constant
i.e q=constant OR CV=constant .............(1)
Capacitance of parallel plate capacitor C=
d
Aϵ
o
So if the distance between the plates is increased, then the capacitance will decrease which is compensated by the increase in voltage across the capacitor according to equation (1).
Also the energy stored in the capacitor E=
2C
q
2
⟹E∝
C
1
(∵q=constant)
Thus energy will increase due to the decrease in capacitance.
Explanation:
Answer:
Her final velocity is 46 m/s :-)
Explanation:
Answer:
I = 2.33 µA
Explanation:
given,
Effective resistance (R)= 300 Ω
Voltage of signal (V)= 700 µV
current flow in the antenna = ?
Using ohm's law
V = I R
where I is the current flow
I = 2.33 x 10⁻⁶ A
I = 2.33 µA
Hence, the current flow in the antenna downloaded is equal to I = 2.33 µA
Answer:
<h2><em>
34.46m</em></h2>
Explanation:
Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;
v is the final velocity of the bicyclist = 26m/s
u is the initial velocity of the bicyclist = 0m/s
a is the acceleration due to gravity = 9.81m/s
s is the distance covered during travel
Substitute the given parameters into the formula above to get the distance traveled
26² = 0² + 2(9.81)s
676 = 19.62s
Divide both sides by 19.62
676/19.62 = 19.62s/19.62
s = 34.46m
<em>The distance traveled by the bicyclist during the race is 34.46m</em>