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Angelina_Jolie [31]
3 years ago
15

For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.

Chemistry
1 answer:
FromTheMoon [43]3 years ago
7 0

The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:

A. Hg₂SO₄

B. Na₂SO₄

C. Na⁺

D. NO₃⁻

E. SO₄⁻²

F. Hg₂(NO₃)₂

G. NaNO₃

H. Hg⁺²

Answer:

C, D, E, H

Explanation:

The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.

Thus, the reaction given:

Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃

So, let's do the dissociation.

Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;

Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;

HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;

NaNO₃ is formed by the ions Na⁺ and NO₃⁻.

Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.

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Explanation:

Nonpolar compounds do not dissolve in water. The attractive forces that operate between the particles in a nonpolar compound are weak dispersion forces. However, the nonpolar molecules are more attracted to themselves than they are to the polar water molecules.

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If the pressure of a gas sample is quadrupled and the absolute temperature is doubled, by what factor does the volume of the sam
Natasha_Volkova [10]

Answer:

D) 1/2

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given,

P₂ = 4P₁

T₂ = 2T₁

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{P_1}\times {V_1}}{T_1}=\frac {{4\times P_1}\times {V_2}}{2\times T_1}

V_2=\frac{1}{2}\times V_1

<u>The volume change by half of the original.</u>

7 0
3 years ago
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A sample of gas has a volume of 20.0 liters at 22.0° C. If the pressure remains constant, what is the volume at 100.0° C?
miv72 [106K]
The problem applies Charles' law since constant pressure with varying volume and temperature are given. Assuming ideal gas law, the equation to be used is \frac{ V_{1} }{ T_{1} }=\frac{ V_{2} }{ T_{2} }. We make sure the temperatures are expressed in Kelvin, hence the given added with 273. The volume 2 is equal to 25.2881 liters.
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A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.
ArbitrLikvidat [17]

Answer:

The answer to your question is   P2 = 170.9 torr

Explanation:

Data

Volume 1 = 12.1 l                                Volume 2 = 21.1 l

Temperature 1 = 241 °K                      Temperature 2 = 298°K

Pressure 1 = 546 torr                           Pressure 2 = ?

Process

To solve this problem use the combined gas law.

                P1V1/T1 = P2V2/T2

-Solve for P2

                P2 = T1V1T2 / T1V2

-Substitution

                P2 = (241 x 12.1 x 298) / (241 x 21.1)

-Simplification

                P2 = 868997.8 / 5085.1

-Result

                P2 = 170.9 torr

       

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What is in with those numbers? H2O?
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Answer:

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