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Jet001 [13]
3 years ago
10

Gerald's science teacher mixed room temperature samples of hydrochloric acid and sodium hydroxide in a large beaker. The solutio

n still looked clear like water, but when the students carefully touched the beaker one at a time, it felt warm to the touch.
Why did the beaker most likely feel warm?
Chemistry
2 answers:
kozerog [31]3 years ago
6 0
 <span>HCl is a strong acid and NaOH is a strong base, so mixing them together will produce a lot of heat. The products are salt or Sodium chloride (NaCl) and water (H2O). Since one is an acid and one is a base they will neutralize each other. I hope this helps</span>
Alchen [17]3 years ago
3 0

Answer:

The beaker feels warm because is an exothermic reaction

Explanation:

An exothermic reaction is one that releases energy, in this case, through heat. Then, when HCl, a strong acid, and NaOH, a strong base, are mixed together it is produced a salt and water with a release of energy. The reaction is expressed as:

HCl + NaOH ------> NaCl + HCl + Energy

This happens because the energy of the products is lower than the energy of the reactants.

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The entire woodpecker population would  be DESTROYED
5 0
3 years ago
Read 2 more answers
What is the most important role that water plays for living organisms
LuckyWell [14K]

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- it gives us nutrients and minerals

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4 0
3 years ago
Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.970 atm when 25.5 g of glucose is consumed in this re
katrin2010 [14]

I believe the balanced chemical equation is:

C6H12O6 (aq) + 6O2(g) ------> 6CO2(g) + 6H2O(l) 

 

First calculate the moles of CO2 produced:

moles CO2 = 25.5 g C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)

moles CO2 = 0.8493 mol

 

Using PV = nRT from the ideal gas law:

<span>V = nRT  / P</span>

V = 0.8493 mol * 0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm

<span>V = 22.28 L</span>

6 0
3 years ago
A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental
OleMash [197]

Answer:

the empirical (lowest raios) is

C2H4Cl    

Explanation:

A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental analysis, it was determined that the compound is composed of 24.27% carbon.

What is the empirical formula of this compound?

the compound has ONLY C, H, and Cl

the % Cl  = 100% - 24.27% -4.03% = 71.7%

in 100 gm, there are 71.7 gm Cl, 24.27 gm C, and 4.03 gm H

the number of moles are Cl=71.7/70.91 =1.01= ~ 1

                                          C = 24.27/12.0 = 2.02 =~ 2

                                           H = 403/1.01 = 3.97 =~   4

so   the empirical (lowest raios) is

C2H4Cl      

                                 

                               

3 0
3 years ago
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
3 years ago
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