I am sorry i wish i could help you but i dont know the answer either.
The alloy has a density of 21.186g/cc. So for a kilogram or 1000 grams/21.186 g/cc= 45.7 cc. So the answer is 45.7 cc of the allow to make up a kilogram which shows that the density of the allow can be used to calculate the volume of a larger mass ie the kilogram.
Answer:
4.12 mol
Explanation:
Given data:
Moles of LiOH required = ?
Volume of solution = 4.2 L
Molarity of solution = 0.98 M
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
we will calculate the moles from above given formula.
0.98 M = number of moles / 4.2 L
0.98 M × 4.2 L = number of moles
Number of moles = 0.98 M × 4.2 L
Number of moles = 4.12 mol (M = mol/L)
Answer:
0.80 Moles of Hydrochloric Acid would be required to produce 0.40 Moles of hydrogen gas due to the equation ratios
Explanation:
How many moles of hydrochloric acid are required to produce .40 moles of hydrogen gas?
Hydrochloric acid = HCl
Hydrogen gas = H2
H = 1+
Cl = 1-
HCL = H2 + Cl2
2HCl = H2 + Cl2
2:1:1
0.80 = 0.40 + 0.40
