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Jet001 [13]
3 years ago
10

Gerald's science teacher mixed room temperature samples of hydrochloric acid and sodium hydroxide in a large beaker. The solutio

n still looked clear like water, but when the students carefully touched the beaker one at a time, it felt warm to the touch.
Why did the beaker most likely feel warm?
Chemistry
2 answers:
kozerog [31]3 years ago
6 0
 <span>HCl is a strong acid and NaOH is a strong base, so mixing them together will produce a lot of heat. The products are salt or Sodium chloride (NaCl) and water (H2O). Since one is an acid and one is a base they will neutralize each other. I hope this helps</span>
Alchen [17]3 years ago
3 0

Answer:

The beaker feels warm because is an exothermic reaction

Explanation:

An exothermic reaction is one that releases energy, in this case, through heat. Then, when HCl, a strong acid, and NaOH, a strong base, are mixed together it is produced a salt and water with a release of energy. The reaction is expressed as:

HCl + NaOH ------> NaCl + HCl + Energy

This happens because the energy of the products is lower than the energy of the reactants.

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Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) O -7
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Explanation:

For an isothermal process equation will be as follows.

                W = nRT ln\frac{P_{1}}{P_{2}}

It is given that mass is 10 kg/s or 10,000 g/s (as 1 kg = 1000 g). So, calculate number of moles of water as follows.

                    No. of moles = \frac{mass}{\text{molar mass}}

                                           = \frac{10000 g/s}{18 g/mol}

                                           = 555.55 mol/s

                                           = 556 mol/s (approx)

As T = 50^{o}C or (50 + 273.15) K = 323.15 K. Hence, putting the given values into the above formula as follows.

                  W = nRT ln[/tex]\frac{P_{1}}{P_{2}}[/tex]

                      = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times ln\frac{1}{10}    

                     = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times -2.303    

                     = -3440193.809 J/s

Negative sign shows work is done by the pump. Since, 1 J = 0.001 kJ. Therefore, converting the calculated value into kJ as follows.

                     3440193.809 J/s \times \frac{0.001 kJ}{1 J}

                          = 3440.193 kJ/s

                          = 3451 kJ/s (approx)

Thus, we can conclude that the pump work is 3451 kJ/s.

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3 years ago
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