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Radda [10]
3 years ago
6

6.0L of a gas exert a pressure of 2.5 atm. When the pressure is increased to 10.0atm what is the new volume of the gas

Chemistry
1 answer:
jeka57 [31]3 years ago
7 0

Answer:

<h2>1.5 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{6 \times 2.5}{10}  =  \frac{15}{10}  =  \frac{3}{2}  \\

We have the final answer as

<h3>1.5 L</h3>

Hope this helps you

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Answer:

0.4 M

Explanation:

M=moles/Liters

Convert grams to moles (446/223.37=1.99668711)

Convert 5000 mL to liters (5000/1000)

Plug in the values and solve

M=2/5

M=0.4

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At 258C, Kp 5 2.9 3 1023 for the reactionNH4OCONH21s2m 2NH31 g21 CO21 g2In an experiment carried out at 258C, a certain amount o
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Answer:

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Explanation:

<em>At 25ºC, Kp = 2.9 x 10⁻³ for the reaction NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g). In an experiment carried out at 25ºC, a certain amount of NH₄OCONH₂ is placed in an evacuated rigid container and allowed to come to equilibrium. Calculate the total pressure in the container at equilibrium.</em>

Step 1: Make an ICE chart

Solid and liquids are ignored in ICE charts.

       NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g)

I                                            0             0

C                                        +2x           +x

E                                          2x             x

Step 2: Write the pressure equilibrium constant expression (Kp)

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pNH₃ = 2x = 2(0.090 atm) = 0.18 atm

pCO₂ = x = 0.090 atm

The total pressure is:

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