Answer;
30.6 m
Explanation;
All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².
Distance traveled by an object falling down under a constant acceleration will be given the formula;
s = ut² + 1/2(gt²); but u the initial velocity is o
thus;
S =1/2(gt²)
= 0.5 × 9.81 × 2.5 ²
= 30.65
≈ 30.6 m
Answer:
Explanation:
given,
length of ladder = 10 ft
let x be the distance of the bottom and y be the distance of the top of ladder.
x² + y² = 100
differentiating with respect to time we get
..............(1)
when x = 8 and y = 6 and when \dfrac{dx}{dt} = 1.4ft/s
from equation (1)
now,
let the angle between the ladders be θ
y = xtan θ
Answer:
10392.30N
Explanation:
We proceed by computing the individual force exerted by the boats
For the first boat
The angle is 30 degree to the vertical
Hence
Force = F cos θ
F=6000 cos 30
F=6000*0.866
F=5196.15 N
Since the boats are two and also at the same angle and also exerting the same force
The Net force = 2*5196.15
Net force=10392.30N
From 50km/h to 0km/h in 0.5s we need next acceleration:
First we convert km/h in m/s:
50km/h = 50*1000/3600=13.8888 m/s
a = v/t = 13.88888/0.5 = 27.77777 m/s^2
Now we use Newton's law:
F=m*a
F=1700*27.7777 = 47222N
An air mass is a large pocket of air with a uniform temperature and humidity
