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kondor19780726 [428]
3 years ago
8

A car travels 82 meters do North and 14 seconds the car turns around and travels 44 m due south in four seconds what is the magn

itude of the average velocity of the car during the full travel time?
Physics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

2.11 m/s

Explanation:

Take north to be positive and south to be negative.

Average velocity = displacement / time

v = (82 m + -44 m) / (14 s + 4 s)

v = 2.11 m/s

The velocity is positive, so it is 2.11 m/s north.  The magnitude of the velocity is 2.11 m/s.

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Answer:

a) ||\vec F_{B}||=62.664\,N, b) From east to west.

Explanation:

Vectorially, the magnetic force can be calculed by the following formula:

\vec F_{B} = i\cdot \vec l\, \times \, \vec B

The cross product is:

\vec F_{B} = \left|\begin{array}{ccc}i&j&k\\1015000\,A\cdot m&0\,A\cdot m&0\,A\cdot m\\22.471\times 10^{-6}\,T&-61.738\times 10^{-6}\,T&0\,T\end{array}\right|

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b) The direction of the magnetic force is:

From east to west.

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Explanation:

<u>Given the following data;</u>

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