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Leya [2.2K]
3 years ago
5

The foot of a ladder is 6m away from a wall. if the top of the ladder rest 8 feet up on the wall,how long is the ladder?

Physics
1 answer:
babunello [35]3 years ago
5 0

To solve this we can use Pythagorean's theorem for right triangles. The formula describes the longest side of a right triangle ( a triangle with a 90degree ). The side opposite to this angle equals the square root of the sum of the squares of the other two shorter sides. Given this equation, we have the length of the ladder as the longest side (hypotenuse) which is opposite the angle between the plane and the wall, given the height it makes with the wall 8 feet and distance of the other end of the ladder at 6m away we have below


Length of ladder = sqrt ((6 m)^2+(2.4384m)^2)

Note that 8 feet was converted to meter = 2.4384

Length of ladder is = sqrt (36 + 5.94579456) = 6.5 meters approximately

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A plane electromagnetic wave travels northward. At one instant, its electric field has a magnitude of 9.6 V/m and points eastwar
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Answer:

The values is  B  = 3.2 *10^{-8} \  T

The  direction is out of the plane

Explanation:

From the question we are told that

  The  magnitude of the electric field is  E  =  9.6 \  V/m

 

The  magnitude of the magnetic field is mathematically represented as

       B  = \frac{E}{c}

where c is the speed of light with value

      B  = \frac{ 9.6}{3.0 *10^{8}}

     B  = 3.2 *10^{-8} \  T

Given that the direction off the electromagnetic wave( c ) is  northward(y-plane ) and  the electric field(E) is eastward(x-plane ) then the magnetic field will be acting in the out of the page  (z-plane  )

     

3 0
3 years ago
Will give brainliest, Pleaseee help!!!
puteri [66]

Answer:

below

Explanation:

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Peak hydraulic systems demands may be met by the use of what ?
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8 0
3 years ago
Read 2 more answers
A brave child decides to grab onto an already spinning merry‑go‑round. The child is initially at rest and has a mass of 34.5 kg.
rodikova [14]

Answer:

the moment of inertia of the merry go round is 38.04 kg.m²

Explanation:

We are given;

Initial angular velocity; ω_1 = 37 rpm

Final angular velocity; ω_2 = 19 rpm

mass of child; m = 15.5 kg

distance from the centre; r = 1.55 m

Now, let the moment of inertia of the merry go round be I.

Using the principle of conservation of angular momentum, we have;

I_1 = I_2

Thus,

Iω_1 = I'ω_2

where I' is the moment of inertia of the merry go round and child which is given as I' = mr²

Thus,

I x 37 = ( I + mr²)19

37I = ( I + (15.5 x 1.55²))19

37I = 19I + 684.7125

37I - 19 I = 684.7125

18I = 684.7125

I = 684.7125/18

I = 38.04 kg.m²

Thus, the moment of inertia of the merry go round is 38.04 kg.m²

7 0
3 years ago
Read 2 more answers
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