Answer:
New volume V2 = 92.7 Liter (Approx)
Explanation:
Given:
V1 = 106 l
T1 = 45 + 273.15 = 318.15 K
P1 = 740 mm
T2 = 20 + 273.15 = 293.15 K
P2 = 780 mm
Find:
New volume V2
Computation:
P1V1 / T1 = P2V2 / T2
(740)(106) / (318.15) = (780)(V2) / (293.15)
New volume V2 = 92.7 Liter (Approx)
You could argue that any solution with water in it has an equilibrium in it of some sort. If a solution is over saturated there is an equilibrium between the dissociated and solid solute (for example NaCl(s)⇄Na⁺(aq)+Cl⁻(aq) when in water). Even if the solution is not over saturated, water always has the reaction 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq) since water can act as both an acid and a base (this reaction is also always at equilibrium and the equilibrium constant is 1×10⁻¹⁴).
Since we usually ignore the autoionization of water (unless dealing with acid base chemistry), I think the answer your teacher is looking for is over saturated solutions.
I hope this helps. Let me know if anything is unclear or if you need a different answer.
That guy is a hacker beware!^
I don’t know I just want the points but I think it’s : C
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa
∴ on rearranging above eq., we get V2 =
∴ V2 = 4 m3