How many molecules of liquid methanol are in 10.00 mL of methanol, given its density is 0.7918 g/mL?
1 answer:
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Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol =
=
=
= 0.894 mol
Hence, number of moles of water =
= 2.77
As glycol is dissolved in water.
So, the molality =
= 17.9
Therefore, the expected freezing point =
=
Thus, we can conclude that the expected freezing point is .
Here we have to write a simple equation which describes the action of the enzyme catalase.
The equation is: The concentration of the complex [ES] =
Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P
Where E, S, ES and P are enzyme, substrate, complex and product respectively.
The concentration of the complex [ES] = , where
is the Michaelis constant.
[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.