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miss Akunina [59]

2 years ago

7

A piece of granite is made up of three basic particles: black, pink, and white particles. If you look at one side of the rock, t

here are more black particles. This is because it is a ________________________ mixture.A.Homogeneousb.Heterogeneous

1 answer:

a_sh-v [17]2 years ago

7 0

A, a heterogeneous ........

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What type of radiation is emitted when chromium-51 decays into manganese-51? Show the nuclear equation that leads you to this an

Anastasy [175]

It's a beta decay
24Cr51 --> 25Mn51 + -1eo

4 0

3 years ago

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Why B-Cl bond is polar?

aniked [119]

Answer:

The difference in the electronegativities of chlorine and boron is 3.0 - 2.0 = 1.0 ; the difference in between chlorine and carbon is 3.0 = 2.5 = 0.5 . Consequently, the B-Cl bond is more polar ; the chlorine atom asrries the partial negative charge because it has higher electronegativity .

Explanation:

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2 years ago

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When rolling a die, find the probability of rolling an even number or rolling a

frozen [14]

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even no = 3/6 = 1/2

no. less than 5 = 4/6 = 2/3

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2 years ago

Three chemistry students measured the length of a copper bar. The recorded lengths were 5.05 cm, 5 cm , and 5.1 cm, What is the

Salsk061 [2.6K]

5.05 + 5 + 5.1 = 15.15cm Then you just divide it by the amount of measurements you had like this:15.15 ÷ 3 = 5.04999971cm Then you can just round it to the 3rd figure: 5.05cm < And that's the mean/average length of the bar. :) (Or the one above if you want all of the decimals too)

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3 years ago

A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w

Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

$Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)$

$c=5760J/^oC$

$\Delta T=0.570^oC$

To calculate the enthalpy change, we use the formula:

$\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J$

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = $\frac{3283.2J}{0.1326g}=24760.181J/g$

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

$\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol$

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2 years ago