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The angle of elevation is = 70° and the distance the airplane travelled in the air is = 17,557ft
<h3>Calculation of the distance travelled</h3>
- To calculate the angle of elevation of the airplane
tan x° = opposite/adjacent
where opposite = 16,500 feet
adjacent = 6,000 ft
tan x° = 16,500 / 6,000
tan x° = 2.75
X = arctan ( 2.75)
X = 70°
- To calculate the distance the airplane travelled in the air Pythagorean Theorem is used.
C² = a² + b²
C² = 16,500² + 6,000²
C² = 272250000 + 36000000
C² = 308250000
C= √308250000
C= 17,557ft
Learn more about Pythagorean Theorem here:
brainly.com/question/343682
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Answer:
10 visits
Step-by-step explanation:
So first let's make an equation, 7.74x + 8.93= 86.33. When you solve for x you get 10.
<span>four over nine of a mile in four over five of an hour
= 4 4
----- / ----
9 5
</span>= 4 5
----- * ----
9 4
= 20
-------
36
= 5
-----
9
answer is : <span>four ninths over four fifths = five over nine mile per hour (first choice)</span>
11 million seventy six thousand eight hundred twenty five