True or false. Air masses mix at fronts?

What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen? (5 points)

konstantin123 [22]

C3 H4 N1 ~~that’s what I think

8 0

3 years ago

mole is equal to 6.022x1023 particles/atoms/molecules. how many chloride ions are presented when 1 mole of sodium chloride is mi

krek1111 [17]

When 1 mole of sodium chloride is mixed with 4 mole of magnesium chloride, the number of chloride ion present will be 5.4198 x $10^{24}$ molecules

<h3>Number of molecules in substances</h3>

1 mole of sodium chloride contains 1 mole of chloride ion according to the following equation:

NaCl ---> $Na^+$ + $Cl^-$

4 moles of magnesium chloride will contain moles of chloride ions according to the following equation:

$4MgCl_2 --- > 4Mg^{2+} + 8 Cl^-$

The total number of moles of chloride ions in solution:

1+8 = 9 moles.

1 mole of a substance = 6.022 x $10^{23}$

Thus, the total number of chloride ions present in the mixture = 9 x 6.022 x $10^{23}$

= 5.4198 x $10^{24}$ molecules

More on number of molecules in substances can be found here: brainly.com/question/11907018

#SPJ1

8 0

2 years ago

Please help me i’m in need!

makkiz [27]

Answer:

balanced............

3 0

3 years ago

The reaction of UO2 with hydrogen ion in aqueous solution 2 UO2 4 H U4 UO22 2 H2O is second order in UO2 and third order overall

Gennadij [26K]

Answer: $rate=k[UO_2^+]^2[H^+]$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The balanced chemical reaction is:

$2UO_2^+4H^+\rightarrow U^{4+}+UO_2^{2+}+2H_2O$

$rate=k[UO_2^+]^n[H^+]^m$

where k = rate constant

n = order with respect to $UO_2^+$ = 2

m = order with respect to $H^+$ = ?

n+ m = 3

2+ m = 3

m = 1

Thus m = order with respect to $H^+$ = 1

$rate=k[UO_2^+]^2[H^+]^1$

4 0

4 years ago

3) The molar mass of a new prescription drug is 287.34 g/mol. If the manufacturer produces 537 moles of

djyliett [7]

Answer: " 145,000 g " .

________________________

Explanation:

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To solve: Let's use a technique known as "dimensional analysis"

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$\frac{287.34 g}{mol}$ * ( 537 mol) = ? g ;

______________________

<u>Note</u>: "g" stands for "grams" ;

______________________

The units of "mol" ["mole(s)"] on the "left-hand side of the equation"

→ "cancel out" ; {since: "mol/mol" = 1 "} ;

_________________

And we have:

(287.34 * 537) g ;

________________

Using a calculator, we do the multiplication to get:

________________

154301.58 g ; We round this to <u>3 (three) significant figures</u>;

since: (287.34 * 537) g ; the limiting number with the "least number of significant figure" is "537" ; which has 3 (three) significant figures;

_______________

As such:

We have 154301.58 g ;

_______________

We round this to 145,000 g ; since:

"154" are the first 3 (three) significant figures in our value:

" 154301.58" ; and the next significant figure, "3" ; is less than "5" ;

If the next significant figure were "0, 1, 2, 3, or 4" ; we would round down to: 145,000 g; such as in our case. If the next significant figure were "5, 6, 7, 8, or 9" , we would round up to: 146,000 g .

__________________

The correct answer is: " 145,000 g ."

7 0

3 years ago