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LekaFEV [45]
3 years ago
14

The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion fo

rces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type.
Chemistry
2 answers:
svetlana [45]3 years ago
7 0

Answer:

NaCl \rightarrow ionic bonds.

N_2 \rightarrow dispersion forces.

HCl \rightarrow dipole-dipole attractions.

HF \rightarrow hydrogen bonds

Explanation:

NaCl is formed between ions Na^+ and Cl^- which makes it an ionic compound having ionic bonding between it's atoms.

N_2 is a covalent non-polar molecule with only week dispersion forces caused by temporary dipoles in the binary molecule.

HCl is a covalent polar molecule with permanent dipoles Hδ+ and Clδ-.

HF consists of both Hydrogen and Fluoride

Anna007 [38]3 years ago
3 0

Answer:

NaCl: ionic, HF: hydrogen bond,  HCl: dipole dipole , F2: dispersion force

Explanation:

complete question is:

The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion forces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type.Identify each of the following ( NaCl, HF, HCl, F2) as Ionic, H Bonding, Dipole or Dispersion.

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Answer: Option (A) is the correct answer.

Explanation:

When there occurs no change in the chemical composition of a substance then it is known as physical property.

For example, mass, volume, density are all physical properties.

Since, the mass of an electron is negligible and an electron holds a negative charge.

Therefore, negatively charged particle with very little mass accurately describes the physical properties of electrons in atoms.

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The number of protons and neutrons in an atom is that atoms __ number.
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Which one of the following pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched? Acid Conjugate Base
vekshin1

Answer : The incorrect option is, (d) NH_4^+/NH_2^-

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

HF+H_2O\rightleftharpoons F^-+H_3O^+

In this reaction, HF is an acid that donate a proton or hydrogen to H_2O base and it forms F^- and H_3O^+ are conjugate base and acid respectively.

In this reaction, HF/F^- are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

HClO+H_2O\rightleftharpoons ClO^-+H_3O^+

In this reaction, HClO is an acid that donate a proton or hydrogen to H_2O base and it forms ClO^- and H_3O^+ are conjugate base and acid respectively.

In this reaction, HClO/ClO^- are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

H_2O+H_2O\rightleftharpoons OH^-+H_3O^+

In this reaction, H_2O is an acid that donate a proton or hydrogen to

In this reaction, H_2O/OH^- are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

NH_4^++H_2O\rightleftharpoons NH_3+H_3O^+

In this reaction, NH_4^+ is an acid that donate a proton or hydrogen to H_2O base and it forms NH_3 and H_3O^+ are conjugate base and acid respectively.

In this reaction, NH_4^+/NH_3 are act as a conjugate acid-base.

(e) The equilibrium reaction will be,

H_3O^++H_2O\rightleftharpoons H_2O+H_3O^+

In this reaction, H_3O^+ is an acid that donate a proton or hydrogen to H_2O base and it forms

In this reaction, H_3O^+/H_2O are act as a conjugate acid-base.

From this we conclude that that, NH_4^+/NH_2^- pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.

Hence, the incorrect option is, (d) NH_4^+/NH_2^-

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