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LekaFEV [45]
2 years ago
14

The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion fo

rces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type.
Chemistry
2 answers:
svetlana [45]2 years ago
7 0

Answer:

NaCl \rightarrow ionic bonds.

N_2 \rightarrow dispersion forces.

HCl \rightarrow dipole-dipole attractions.

HF \rightarrow hydrogen bonds

Explanation:

NaCl is formed between ions Na^+ and Cl^- which makes it an ionic compound having ionic bonding between it's atoms.

N_2 is a covalent non-polar molecule with only week dispersion forces caused by temporary dipoles in the binary molecule.

HCl is a covalent polar molecule with permanent dipoles Hδ+ and Clδ-.

HF consists of both Hydrogen and Fluoride

Anna007 [38]2 years ago
3 0

Answer:

NaCl: ionic, HF: hydrogen bond,  HCl: dipole dipole , F2: dispersion force

Explanation:

complete question is:

The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion forces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type.Identify each of the following ( NaCl, HF, HCl, F2) as Ionic, H Bonding, Dipole or Dispersion.

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RoseWind [281]

Answer:

Marketing affects the consumer mindset by leaving them with the decision of either purchasing a product or not and why it should be purchased or not.

6 0
2 years ago
What is the approximate temperature of 1.4 moles of a gas with a pressure of 3.25 atmospheres in a 4.738-liter container
attashe74 [19]

Answer:

134K

Explanation:

Using the ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (Litres)

n = number of moles (mol)

R = gas constant (0.0821 Latm/Kmol)

T = temperature (K)

Based on the information provided, n = 1.4moles, P = 3.25atm, V = 4.738L, T = ?

3.25 × 4.738 = 1.4 × 0.0821 × T

15.3985 = 0.11494T

T = 15.3985/0.11494

T = 133.969

Approximately;

T = 134K

3 0
2 years ago
How many atoms of fluorine are in 5.6×1022 molecules of MgF2?
VashaNatasha [74]

Answer:You can set up stoichiemetry using the following equation:

(15.6 g MgF2) x (38g F / 62g MgF2) x (6.022x10^23 / 19gF)

= 3.03 x 10^23 molecules of F

or 1.52 x 10^23 molecules of F2

The number of molecules of magnesium fluoride in 15.6 g of MgF2 has to be found.

The molecular mass of MgF2 is 62.3018. 15.6 g of MgF2 is equivalent to 15.6/62.3018 mole of MgF2.

One mole of a gas has 6.02214179*10^23 particles.

15.6/62.3018 mole of MgF2 has (15.6/62.3018)*6.02214179*10^23 molecules of the compound.

(15.6/62.3018)*6.02214179*10^23

=> 1.5079*20^23

If this is rounded to one decimal figure the result is 1.51*10^23.

The number of molecules of MgF2 in 15.6 g of the gas is 1.51*10^23.

3 0
2 years ago
An atom or ion has 41 neutrons, 36 protons, and 36 electrons. Identify the clement symbol, and determine the mass
Paul [167]

The atom is krypton and its symbol is Kr.

the mass number is 41 + 36 = 77

its charge is 0 as it is a noble gas.

7 0
3 years ago
Calculate the percent of composition of oxygen in Mercury (ll) oxide HgO
bekas [8.4K]
Add up the molar mass of Mercury Oxide, and then divide the molar mass of Oxygen by the molar mass of the compound.

So...

mm of Hg + mm of O= 200.59g + 16g= 217g

16g/217g = .0737... x 100 = 7.37%
6 0
3 years ago
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