If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)
Ksp{Zn(OH)₂}=1.2*10⁻¹⁷
2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)
Ksp{Zn(CN)₂}=2.6*10⁻¹³
Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}
Zn(OH)₂ precipitates first
140 s. It would take 140 s to swim 0.150 mi
.
<em>Step 1</em>. Convert the <em>time to seconds</em>
Time = 14 min × (60 s/1 min) + 34.56 s = 840 s + 34.56 s = 874.56 s
<em>Step 2</em>. Convert <em>miles to metres
</em>
Distance = 0.150 mi × (1609.3 m/1 mi) = 241.4 m
<em>Step 3.</em> Calculate the <em>time to swim 241.4 m</em>
Time = 241.4 m × (874.56 s/1500 m) = 140 s
(<em>As of 2012, the men’s freestyle record for 1500 m was 14:31.02</em>.)
Assuming it has no electrical charge, your electron count would be equal to the atomic number.
Answer:
1s2 2s2 2p6 3s2 3p6 3d4 4s2
Explanation:
Cobalt has twenty seven electrons hence Co3+ has twenty four electrons. It has lost three electrons from its valence shell. In filling the orbitals, we keep in mind that the energy of the 4s level is higher than that of the 3s level when a transition metal forms a complex hence the 4s is filled before the 3s level as shown in the answer above.
