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3 years ago

Can the excess reactant control the percentage yield

Chemistry

1 answer:

katrin2010 [14]3 years ago

6 0

Explanation:

when one reactants is in excess, there will always be some left over. The other reactants becomes limiting factor and controls show much of each product is produced.while using excess percentage yields this is at the expense of atom economy.

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What does it mean if you titrated the acid to a 'hot pink' color All of these

Murrr4er [49]

Answer: Too much base was added

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Explanation:

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3 years ago

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

$Q_1=-Q_2$

Mass of steel= $m_1$

Specific heat capacity of steel = $c_1=0.452 J/g^oC$

Initial temperature of the steel = $T_1=2.00^oC$

Final temperature of the steel = $T_2=T=21.50^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2= 105 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=22.00^oC$

Final temperature of water = $T_2=T=21.50^oC$

$Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))$

On substituting all values:

$(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}$

<h3>25.0 grams is the mass of the steel bar.</h3>

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3 years ago

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How many atoms are in .800 g of Ca

Goshia [24]

The answer for this question is 0.8

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3 years ago

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An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar

Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

$372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s$

= 4526 g/s

Now, we will calculate the power as follows.

Power = Fuel consumption rate × -enthalpy of combustion

= $4526 g/s \times -26.5 kJ/g$

= $1.19 \times 10^{5}$ kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is $1.19 \times 10^{5}$ kW.

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3 years ago

A solution that is able to dissolve additional solute is best described as

worty [1.4K]

<h2>Question:</h2>

A solution that is able to dissolve additional solute is best described as _____.

<h2>Answer:</h2>

<h2>D.) Unsaturated </h2>

<u>Unsaturated</u> means the substance is poured into the solvent that can be dissolved. It is a solution (with less solute than the saturated solution) that completely dissolves, leaving with no remaining substances.

<h2>For example:</h2>

If you were to pour olive oil into a glass of water, it will dissolve, so it is <u>unsaturated</u>.

_________

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3 years ago