I believe this question has the following five choices to
choose from:
>an SN2 reaction has occurred with inversion of
configuration
>racemization followed by an S N 2 attack
>an SN1 reaction has taken over resulting in inversion
of configuration
>an SN1 reaction has occurred due to carbocation
formation
>an SN1 reaction followed by an S N 2 “backside”
attack
The correct answer is:
an SN1 reaction has occurred due to carbocation formation
Answer: Since this is merely a Physical Change, it is improper to write it as a chemical equation.
B. 3.0 mol·L⁻¹ NaCl
Explanation:
Freezing point is a colligative property: it depends only on the number of particles in solution.
The for freezing point depression ΔT_f is
ΔT_f = iK_fb
where
i = the number of moles of particles available from one mole of solute
K_f = the molal freezing point depression constant
b = the molal concentration of the solute
All your solutions are aqueous NaCl. They differ only in their concentrations.
Thus, the most concentrated solution will have the greatest freezing point depression and the lowest freezing point.
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