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Kay [80]
3 years ago
5

When naming ionic compounds the ______________ is named first.

Chemistry
1 answer:
grandymaker [24]3 years ago
7 0
The answer is metal. Metals are always named first in ionic compounds, like KNO3 for example. I hope this helps!
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What is in the center of an atom? what is this portion of the atom called?
Ludmilka [50]
The Nucleus: The Center of an Atom. The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels.
6 0
3 years ago
A chunk of ice breaks off a glacier and falls 30.0 m before it hits the water. Assuming it falls freely (there is no air resista
lina2011 [118]

Answer:

The ice chunk will take 2.47 seconds to hit the water.

Explanation:

Height from which ice chunk fell = h = 30.0 m

Initial velocity of the ice chunk = u = 0 m/s

Time taken by ice chunk to cover 30.0 m of height = t

Acceleration due to gravity = g 9.8m/s^2

Using second equation of motion ;

h=ut+\frac{1}{2}gt^2

30.0 m=0 m/s\times t+\frac{1}{2}\times 9.8 m/s^2\times t^2

t=\sqrt{\frac{30.0m/s\times 2}{9.8 m/s^2}}2.47 s

The ice chunk will take 2.47 seconds to hit the water.

7 0
3 years ago
Write the cations and anions present in NaCl​
pochemuha

In table salt, sodium chloride, sodium is the cation (Na+) and chloride is the anion (Cl-).
6 0
3 years ago
Write a balanced equation for the reaction between sulphuric acid and potassium hydroxide
Musya8 [376]
H2SO4 + 2KOH --> K2SO4 + 2H2O
3 0
3 years ago
Nitric oxide reacts with chlorine to form nocl. the data refer to 298 k. 2no(g) + cl2(g) → 2nocl(g) substance: no(g) cl2(g) nocl
tigry1 [53]

Answer:

- 10.555 kJ/mol.

Explanation:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

Where, ∆G°rxn is the standard free energy change of the reaction (J/mol).

∆H°rxn is the standard enthalpy change of the reaction (J/mol).

T is the temperature of the reaction (K).

∆S°rxn is the standard entorpy change of the reaction (J/mol.K).

  • Calculating ∆H°rxn:

∵ ∆H°rxn = ∑∆H°products - ∑∆H°reactants

<em>∴ ∆H°rxn = (2 x ∆H°f NOCl) - (1 x ∆H°f Cl₂) - (2 x ∆H°f NO) </em>= (2 x 51.71 kJ/mol) - (1 x 0) - (2 x 90.29 kJ/mol) = - 77.16 kJ/mol.

  • Calculating ∆S°rxn:

∵  ∆S°rxn = ∑∆S°products - ∑∆S°reactants

<em>∴ ∆S°rxn = (2 x ∆S° NOCl) - (1 x ∆S° Cl₂) - (2 x ∆S° NO) </em>= (2 x 261.6 J/mol.K) - (1 x 223.0 J/mol.K) - (2 x 210.65 J/mol.K) =<em> - 121.1 J/mol.K. = - 0.1211 kJ/mol.K.</em>

<em></em>

  • Calculating ∆G°rxn:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

<em>∴ ∆G°rxn = ∆H°rxn - T∆S°rxn </em>= (- 77.16 kJ/mol) - (550 K)(- 0.1211 kJ/mol.K) = <em>- 10.555 kJ/mol.</em>

4 0
3 years ago
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