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noname [10]
3 years ago
7

Builders and dentists must store plaster of Paris,

Chemistry
1 answer:
eimsori [14]3 years ago
3 0

Answer:

547 L of water vapour

Explanation:

Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20

From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.

Molar mass of gypsum = 172 g/mol

Molar mass of H2O = 18 g/mol

Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour

i.e. 344 g of gypsum produces 54 g of H2O

2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.

Volume of water vapour produced = mass/density

Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour

Therefore 547 L of water vapour are produced

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Explanation:

Density =\frac{Mass}[Volume}

Density of the air ,d= 1.189 g/L

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Density of carbon dioxide gas = d_1=1.830 g/L

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Total density of filled ball with hydrogen gas:

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Mass of the nitrogen gas :

1.165 g/L\times 0.560 L=0.6524 g

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f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

\frac{0.12g +m}{0.560L}>1.189 g/L

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

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Answer:

See explanation

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See figure 1

I hope it helps!

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