Answer:
547 L of water vapour
Explanation:
Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20
From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.
Molar mass of gypsum = 172 g/mol
Molar mass of H2O = 18 g/mol
Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour
i.e. 344 g of gypsum produces 54 g of H2O
2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.
Volume of water vapour produced = mass/density
Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour
Therefore 547 L of water vapour are produced
