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erma4kov [3.2K]
3 years ago
13

Who proposed a periodic table that accommodated for the discovery of new elements?

Chemistry
1 answer:
NeX [460]3 years ago
3 0
I think William Ramsey
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Identify the name of the compound Cr2(CO3)3.
kompoz [17]
Cr2(CO3)3 is Chromium (III) Carbonate or Chromic Carbonate. 

It is composed of Chromium, Carbon, and Oxygen. Chromium has 2 atoms, Carbon has 3 atoms, and Oxygen has 9 atoms. 

This compound is composed of 36.6% Chromium, 12.7% Carbon, and 50.7% Oxygen.
7 0
4 years ago
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Has earth always had the same land masses and oceans that it has today? What will happen in the future, will they stay in the sa
icang [17]

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3 years ago
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How many moles of h2o are produced when 3.25 moles of o2 react in 2c2h6 + 7o2 ---> 4co2 + 6h2o
Alenkinab [10]

Answer:

2.78 moles of water are produced.

Explanation:

Given data:

Number of moles of H₂O produced = ?

Number of moles of oxygen react = 3.25 mol

Solution:

Chemical equation:

2C₂H₆ + 7O₂       →     4CO₂ + 6H₂O

Now we will compare the moles of water with oxygen.

                O₂          :          H₂O

                 7            :           6

               3.25        :           6/7×3.25 = 2.78 mol

5 0
3 years ago
A person's heartbeat is 66 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th
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5 0
3 years ago
A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K
SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

<u>Explanation:</u>

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}

              = 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$T= \frac{PV}{nR}

T = $\frac{0.56  \times 0.56}{0.08205 \times 0.0047}

 = 813 K

So the temperature of the gas sample is 813 K.

5 0
3 years ago
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