Answer:
1.2044 x 10^24 particles
Explanation:
Assuming this is<u> STP</u>....then this is 2 moles ( each mole = 22.4 L/mole)
2 moles = 2 * 6.022 x 10^23 = 1.2044 x 10^24
Answer:
Explanation:
Given that ;
Compound H is optically active and have a molecular formula of C6H10 and therefore undergo catalytic hydrogenation. Catalytic hydrogenation involves the use Platinum/Nickel to produce C6H12
i.e
The proposed H and I structures are shown in the diagrams attached below .
compound H represents 3- methyl cyclopentene
compound I represents methyl cyclopentane
However; 3- methyl cyclopentene posses just only one chiral carbon which is optically active at the third position and it R and S enantiomers are shown in the second diagram below.
Answer and Explanation: Sample A is a <u>mixture</u>. Solubility is characteristics of each substance, which means a substance can be distinguished from other substances and can be useful to separate mixtures.
In Sample A, when is added different volumes of water, the resulting powder has different mass. This means there are more than one substance forming the yellow cube. Therefore, sample A is a mixture.
Sample B is a <u>pure</u> <u>substance</u>. Each substance has its own melting point. Whe na pure substance reaches its melting point, temperature is constant until all of that substance is melted. In sample B, temperature is stable at 66.2°C and then, after all the powder is melted, it rises again. Therefore, sample B is a pure substance.
Sodium
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Answer:
Oxidation is the loss of electrons, that is, addition of electronegetive elements, example is addition of oxygen. Also, removal of electropositive elements, example is removal of hydrogen.
Explanation: a) In the presence of excess oxygen, propane burns in air, which gives the following chemical equation:
C3H8 + 5O2⇒ 3CO2 + 4H2O +Heat
b) When insufficient oxygen or too much oxygen is present for complete combustion, the following equation is given:
2C3H8 + 9O2 ⇒ 4CO2 + 2CO + 8H2O + Heat
c) At the anode( negative terminal): O∧2- ⇒ O + e
Oxygen accepts electron.
d) At cathode ( positive terminal): H∧+ + e∧- ⇒ H
Hydrogen donates electron
d) Nernst equation for reversal potential is given as follows:
E= RT/zF In{ion outside cell}/{ion inside cell}= 2.303 RT/zF In{ion outside cell}/{ion inside cell}
