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Rudik [331]
4 years ago
14

The boat can travel with a speed of 16 km>h in still water. The point of destination is located along the dashed line. If the

water is moving at 4 km>h, determine the bearing angle u at which the boat must travel to stay on course.
Physics
1 answer:
Nostrana [21]4 years ago
6 0

Answer:

the bearing angle at which the boat must travel to stay on course is 75.5°

Explanation:

To determine the bearing angle  at which the boat must travel to stay on course;

we construct a right angled triangle, with the speed of water adjacent to the speed of the boat which is the hypotenuse.

The angle between them is the bearing angle at which the boat must travel to stay on course.

Let the angle between the still water and boat = θ

Cos θ = 4/16

Cos θ = 0.25

θ = cos⁻¹ (0.25)

θ  =  75.5°

Therefore, the bearing angle at which the boat must travel to stay on course is 75.5°

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The moon is 3x10^5 km away from Nepal and the mass of the moon is 7x10^22 kg. Calculate the force with which the Moon pulls ever
hammer [34]

Answer:

Approximately 5.19 \times 10^{-5}\; \rm N.

Explanation:

Let G denote the gravitational constant. (G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}.)

Let M and m denote the mass of two objects separated by r.

By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:

\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}.

In this question: M = 7 \times 10^{22}\; \rm kg is the mass of the moon, while m = 1\; \rm kg is the mass of the water. The two are r = 3\times 10^{5}\; \rm km apart from one another.

Important: convert the unit of r to standard units (meters, not kilometers) to reflect the unit of the gravitational constant G.

\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m.

\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}.

5 0
3 years ago
What type of wave vibrates parallel to the direction of travel
Irina-Kira [14]

Answer: Longitudinal waves

Explanation: For a sound wave traveling through air, the vibrations of the particles are best described as longitudinal. Longitudinal waves are waves in which the motion of the individual particles of the medium is in a direction that is parallel to the direction of energy transport

5 0
3 years ago
If an element has a charge of 1+, how many more protons does it have than electrons?
Vlada [557]
If an element has a charge of +1, there is 1 more proton than electrons.

A proton has a charge of +1
A neutron has a charge of 0
A electron has a charge of -1.

For there to be a charge of 0, there would be the same amount of charges for both proton and neutron. To get a charge of 1, you will need 1 more proton.


hope this helps
7 0
3 years ago
The diagram below represents a horizontal force of 20 newtons applied to a 5.0 kilogram box to push it and
andreev551 [17]

Answer:

20 N

Explanation:

There are two forces acting on the box:

- The force of push, F, forward, of magnitude F = 20 N

- The force of friction, F_f, backward

So, the equation of motion for the box is

F-F_f = ma

where

m = 5.0 kg is the mass of the box

a is its acceleration

The box is sliding at constant velocity: this means that its acceleration is zero

a = 0

So, the equation becomes

F-F_f = 0

Therefore, we can find the magnitude of the force of friction:

F_f = F =  20 N

8 0
3 years ago
The gravitational acceleration on the moon is about one-sixth the size of the gravitational acceleration on Earth. According to
photoshop1234 [79]

Answer: If the gravitacional acceleration is 1/6 of Earth's gravitational acceleration, it means that moon's gravitational acceleration is less than Earth's. Also, if the gravitational acceleration is less than Earth's, the astronaut's weight decreases since we calculate it multiplying his body mass by the gravity in the place given.

On Earth, an astronaut that is 70kg weights 70kg * 9.8 m/s² = 686N

On the Moon, the same astronaut would weight 70kg * 9.8 m/s² * 1/6 = 114,3 N

So, the astronaut’s weight decreases because the moon’s gravitational acceleration is less than Earth’s.

5 0
4 years ago
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