Water can't cool at a single temperature. It must start at a higher temperature, and drop to a lower temperature in order to cool. Unless we know the other temperature, there is no way to calculate the amount of thermal energy released.
Explanation:
The only flaw I can find is you squared 3 instead of cubing it and it will be 27X^4 instead of 9x^4.
This reduces the amount slightly, but the number is still incredibly high (about 10 ^ 5 L is what I've calculated). Your professor might want to point out that this will not be a effective experiment due to the large volume of saturated
The Ksp value of Ca(OH)2 on the site (I used 5.5E-6 [a far more soluble compound than Al(OH)3]) and estimated how much of it will be needed. My calculation was approximately 30 ml. If you were using that much in the experiment, it implies so our estimates for Al(OH)3 are right, that the high amount is unreasonably big and that Al(OH)3 will not be a suitable replacement unless the procedure was modified slightly.
The volume of gas that exerts a pressure of 457 mmhg if exerted a pressure of 2.50 atm when its volume was 25.0ml is calculated as follows
by use of Bolyes law formula that is P1V1=P2V2
P1= 457mmhg
V1=?
P1 = 2.50 atm = 2.50 x760 = 1900mmhg
V2= 25,0 ml
V1 from the formula above = P2V2/P1
= 1900mm hg x25 ml/ 457 mm hg = 104 ml
Answer:
D. The discovery of new evidence.
D is correct because it's the only one that would give proof and science relies on proof.
Length=The distance between two points
Mass=The amount of matter contained in a body
Time=The interval or duration between two events
Temperature=The hotness and coldness of a body