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STALIN [3.7K]
3 years ago
15

How many milligrams are in 2.5 kg?

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

There are 2500000 milligrams in 2.5 kg

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In the reaction catalyzed by the pyruvate dehydrogenase complex, the two carbons constituting the acetyl group are
lara [203]

Transferred to the lipoamide by an earlier intermediate in the process.

The pyruvate dehydrogenase complex (PDC) is a mitochondrial multienzyme complex composed of three different enzymes

<h3>What reaction is catalyzed by enzyme 2 of the pyruvate dehydrogenase complex ?</h3>

the pyruvate dehydrogenase complex is the bridge between glycolysis and the citric acid cycle

  • Five coenzymes are used in the pyruvate dehydrogenase complex reactions: thiamine pyrophosphate or TPP, flavin adenine dinucleotide or FAD, coenzyme A or CoA, nicotinamide adenine dinucleotide or NAD, and lipoic acid.
  • during the reactions catalyzed by the pyruvate dehydrogenase complex, it is first reduced to dihydrolipoamide, a dithiol or the reduced form of the prosthetic group, and then, reoxidized to the cyclic form.

Learn more about Pyruvate dehydrogenase complex here:

brainly.com/question/16346028

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4 0
2 years ago
When a 2 kg log is burned, it produces 0.5 kg of ash. Explain why the mass of the ash is less than the mass of the log. In other
Lostsunrise [7]

Answer:

my mass turned into gasses and other substances besides ash

Explanation:

burning a log products smoke and ash. the smoke takes some mass and the ash takes the rest.

3 0
3 years ago
During the formation of an ionic compound, the element with the higher ionization energy will gain electrons.
Lesechka [4]
False because you have to take it out and do it right
8 0
3 years ago
Could someone explain how they got this answer, explain step by step plz
gulaghasi [49]

Answer:

6.018 amu

Explanation:

Let 6–Li be isotope A.

Let 7–Li be isotope B.

Let the abundance of 6–Li be A%

Let the abundance of 7–Li be B%

The following data were obtained from the question:

Atomic mass of isotope A (6–Li) =.?

Atomic mass of isotope B (7–Li ) = 7.015 amu.

Abundance of 7–Li (B%) = 92.58%

Abundance of 6–Li (A%) = 100 – B% = 100 – 92.58 = 7.42%

Atomic mass of Lithium = 6.941amu

The atomic mass of isotope A (6–Li) can be obtained as follow:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

6.941 = [(mass of A x 7.42)/100] + [(7.015x92.58)/100]

6.941 = [(mass of A x 7.42)/100] + 6.494487

(mass of A x 7.42)/100 = 6.941 – 6.494487

(mass of A x 7.42)/100 = 0.446513

Mass of A x 7.42 = 100 x 0.446513

Mass of A x 7.42 = 44.6513

Divide both side by 7.42

Mass of A = 44.6513 / 7.42

Mass of A = 6.018 amu

Therefore, the mass of 6–Li is 6.018 amu

7 0
3 years ago
In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is
Vera_Pavlovna [14]
6.02x10^23 atoms is the answer
8 0
3 years ago
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