Simplify: 2(-3x – 6) -6x + 12 A B -62 – 12 -6.3 4 sh D-60 - 8
1 answer:
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Answer:
Step-by-step explanation:
<u>Multiplying both sides by 2</u>
<u>Subtracting 36 to both sides</u>
<u>Dividing both sides by 4</u>
OR
Answer:
46.67% probability that they flew with airline B.
Step-by-step explanation:
We have these following probabilities:
A 40% probability that a traveler chooses airline A.
A 35% probability that a traveled chooses airline B.
A 25% probability that a traveler chooses airline C.
If a passenger chooses airline A, a 10% probability that he arrives late.
If a passenger chooses airline B, a 15% probability that he arrives late.
If a passenger chooses airline C, a 8% probability that he arrives late.
If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?
This can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
So
What is the probability that the traveler flew with airline B, given that he was late?
P(B) is the probability that he flew with airline B.
So
P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.
P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).
So
Probability
46.67% probability that they flew with airline B.