The distance covered by Arthur is
3t
The distance covered by Betty from where Arthur started is
100 - 2t
They meet each other when this distance is equal
3t = 100 - 2t
t = 20 s
Since the dog has a constant speed of 5m/s, the distance that Spot has run is
5 m/s (20s) = 100 m
The final position of the object after 2 s is 11 m.
Motion: This can be defined as the change in position of a body.
⇒ Formula:
- x = x₀+v₀t+1/2(at²)........................ Equation 1
⇒ Where:
- x = Final position of the object
- x₀ = Starting position
- v₀ = Starting velocity
- t = time
- a = acceleration
From the question,
⇒ Given:
- x₀ = 4.5 m/s
- t = 2 s
- x₀ = 2m
- a = 0 m/s²
⇒ Substitute these values into equation 1
- x = 2+(4.5×2)+1/2(0²×2)
- x = 2+9+0
- x = 11 m
Hence, The final position of the object after 2 s is 11 m
Learn more about motion here: brainly.com/question/15531840
Explanation:
Spring is stretched by force f to distance
"X"
now here by force balance we can say
f = kx
k = !
now here we will we say that energy stored in the spring will convert into kinetic energy
kx² = mv²
(x² = mv²
now solving above equation we will have
PART 2)
now for half of the extension again we can use energy conservation
ka²-k(x/2)² = 1 {mv²
¾fx=mv²
now the speed is given as
3 fr 4m V=
Answer:
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