Explanation:
The given data is as follows.
Electric field (E) =
Charge (e) = C
Formula to calculate the magnitude of force is as follows.
F = qE
=
=
Therefore, we can conclude that magnitude of the force on a calcium ion with charge +e is .
To give a solution to this exercise, it is necessary to apply Gauss's magnetic law in which he proposes the magnetic flux through closed surface is zero.
Our data given are as follows:
Inward flux = 13Wb
Outward flux = 22Wb
Since the field of the second flow is directed OUT of the curved side we need to subtract the values, therefore,
Flux = 22-13