Answer:
(B)
Step-by-step explanation:
The given data set is:
600, 612, 614, 615, 620, 630, 643, 644, 656
since, there is no outlier, then we can use both mean and median in order to find the appropriate measure of the the center.
Mean is the "central" value of a set of numbers or data set values, thus it can be used to calculate the appropriate measure of the center, thus
![Mean=\frac{No. of observations}{Total number of observations}](https://tex.z-dn.net/?f=Mean%3D%5Cfrac%7BNo.%20of%20observations%7D%7BTotal%20number%20of%20observations%7D)
![Mean=\frac{600+612+614+615+620+630+643+644+656}{9}](https://tex.z-dn.net/?f=Mean%3D%5Cfrac%7B600%2B612%2B614%2B615%2B620%2B630%2B643%2B644%2B656%7D%7B9%7D)
![Mean=\frac{4990}{9}](https://tex.z-dn.net/?f=Mean%3D%5Cfrac%7B4990%7D%7B9%7D)
![Mean=554.4](https://tex.z-dn.net/?f=Mean%3D554.4)
Median is the middle value of the given data set, thus it can be used to find the appropriate measure of the center, thus
![Median= 620](https://tex.z-dn.net/?f=Median%3D%20620)
therefore, option B is correct.