Which of these electrons is a halogen?

Refer to your completed Table 1d of the recitation guide of ionic compound naming rules to determine whether this statement is t

alexgriva [62]

Answer:

False

Explanation:

Roman numerals are seen in the names of several compounds. They often appear immediately after the name of central atom in the molecule.

These Roman numerals are used to depict the oxidation state of the central atom in the molecule and not to show how many of that ion appear in the formula.

For instance, in carbon IV oxide, the Roman numeral IV shows that the central atom in the compound-carbon is in the +4 oxidation state.

8 0

3 years ago

Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine

dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

pKb1 = - log [kb]

5.1 = - log [kb]

take Antilog of both side

[kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

From the question, 1900 ml of solution contains 1 g of Q

Therefore, 1000 ml of solution will contain........... x g of Q

x = 1000 /1900

x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

= 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

At Equilibrium, Kb = x² / 0.0016

7.94 x 10∧-6 = x² / 0.0016

x = √ 0.0016 × 7.94 x 10∧-6

x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4: Calculating the pH of Quinine

Recall, pOH = - log [OH-]

pOH = - log [1. 127 × 10∧-4]

pOH = 3.948

Also recall that pH + pOH = 14

pH = 14 - 3.948

pH = 10.05

8 0

4 years ago

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.CCl4(g) + (1/2)O2

Elodia [21]

Answer : The value of $K'_c$ for the reaction is, $1.9\times 10^{19}$

Explanation :

The given equilibrium reactions are:

(1) $CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g)$ $K_c=4.4\times 10^9$

(2) $2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$ $K'_c=?$

As we know that, when we are multiplying the equation (1) by 2 then we get the equation (2). Thus, the relation between the two equilibrium constant will be,

$K'_c=(K_c)^2$

So,

$K'_c=(4.4\times 10^9)^2$

$K'_c=1.9\times 10^{19}$

Therefore, the value of $K'_c$ for the reaction is, $1.9\times 10^{19}$

5 0

4 years ago

Define mechanical wave (make sure to use the word “medium”)

Zinaida [17]

Answer:

A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. While waves can move over long distances, the movement of the medium of transmission—the material—is limited. Therefore, the oscillating material does not move far from its initial equilibrium position.

Explanation:

:)

7 0

3 years ago

Round this number to two significant figures. 5206

aivan3 [116]

The answer to this is 5200

7 0

3 years ago

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