Question

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.CCl4(g) + (1/2)O2(g) <----------> COCl2(g) + Cl2(g), Kc = 4.4 x 10^9 at 1,000 KCalculate Kc for the reaction 2CCl4(g) + O2(g) <-------> 2COCl2(g) + 2Cl2(g).A. 4.4 x 10^9B. 8.8 x 10^9C. 1.9 x 10^10D. 1.9 x 10^19E. 2.3 x10^-10

Answer 1

Answer : The value of $K'_c$ for the reaction is, $1.9\times 10^{19}$

Explanation :

The given equilibrium reactions are:

(1) $CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g)$       $K_c=4.4\times 10^9$

(2) $2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)$      $K'_c=?$

As we know that,  when we are multiplying the equation (1) by 2 then we get the equation (2). Thus, the relation between the two equilibrium constant will be,

$K'_c=(K_c)^2$

So,

$K'_c=(4.4\times 10^9)^2$

$K'_c=1.9\times 10^{19}$

Therefore, the value of $K'_c$ for the reaction is, $1.9\times 10^{19}$