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Lena [83]
3 years ago
15

A certain sound is recorded by a microphone. The same microphone then detects a second sound, which is identical to the first on

e except that the amplitude of the pressure fluctuations is larger. In addition to the larger amplitude, what distinguishes the second sound from the first one? View Available Hint(s) A certain sound is recorded by a microphone. The same microphone then detects a second sound, which is identical to the first one except that the amplitude of the pressure fluctuations is larger. In addition to the larger amplitude, what distinguishes the second sound from the first one? It is perceived as higher in pitch. It is perceived as louder. It has a higher frequency. It has a longer wavelength.
Physics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

It is perceived as louder.

Explanation:

Amplitude affects the loudness of sound.

Frequency and wavelength affect the pitch of the sound.

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Which factor determines whether precipitation will be in the form of rain or snow?
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Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by
mylen [45]

Answer:

<em>I must travel with a speed of 2.97 x 10^8 m/s</em>

Explanation:

Sine the spacecraft flies at the same speed in the to and fro distance of the journey, then the time taken will be 6 months plus 6 months

Time that elapses on the spacecraft = 1 year

On earth the people have advanced 120 yrs

According to relativity, the time contraction on the spacecraft is gotten from

t = t_{0} /\sqrt{1 - \beta ^{2} }

where

t is the time that elapses on the spacecraft = 120 years

t_{0} = time here on Earth = 1 year

\beta is the ratio v/c

where

v is the speed of the spacecraft = ?

c is the speed of light = 3 x 10^8 m/s

substituting values, we have

120 = 1/\sqrt{1 - \beta ^{2} }

squaring both sides of the equation, we have

14400 = 1/(1 - \beta ^{2} )

14400 - 14400\beta ^{2} = 1

14400 - 1 = 14400\beta ^{2}

14399 = 14400\beta ^{2}

\beta ^{2} =  14399/14400 = 0.99

\beta = \sqrt{0.99} = 0.99

substitute β = v/c

v/c = 0.99

but c = 3 x 10^8 m/s

v = 0.99c = 0.99 x 3 x 10^8 = <em>2.97 x 10^8 m/s</em>

6 0
3 years ago
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