Answer:
= 15.57 N
= 2.60 N
= 16.98 N
The mass of the bag is the same on the three planets. m=1.59 kg
Explanation:
The weight of the sugar bag on Earth is:
g=9.81 m/s²
m=3.50 lb=1.59 kg
=m·g=1.59 kg×9.81 m/s²= 15.57 N
The weight of the sugar bag on the Moon is:
g=9.81 m/s²÷6= 1.635 m/s²
=m·g=1.59 kg× 1.635 m/s²= 2.60 N
The weight of the sugar bag on the Uranus is:
g=9.81 m/s²×1.09=10.69 m/s²
=m·g=1.59 kg×10.69 m/s²= 16.98 N
The mass of the bag is the same on the three planets. m=1.59 kg
The gravitational force between the two balls is
Explanation:
The magnitude of the gravitational force between two objects is given by:
where :
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
For the balls in this problem, we have
r = 0.74 m
Substituting into the equation, we find the gravitational force between the two balls:
Learn more about gravitational force:
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Answer:
Caustic soda would be least affected by a gas curtailment
Explanation:
Let,
X1= ammonia
X2= ammonium phosphate
X3= ammonium nitrate
X4 = Urea
X5= hydro-fluoric acid
X6= Chlorine
X7= Caustic soda
X8= Vinyl chloride monomer.
Agri chem’s current natural gas usage
= (1200 × 8 + 540 × 10 + 490 × 12 + …)
= 85,680,000 cu. ft. per day
When, the curtailment is 20%, availability is
= 0.8 X 85,680
= 68,554,000 cu. ft. per day
Therefore, the gas constant
= 8X1 + 10X2 + 12X3 + 12X4 + 7X5 + 18X6 + 20X7 + 14X8 ≤68,544
When, the curtailment is 40% availability is
= 0.6 X 85,680
= 51,408,000 cu. ft. per day
Constant = 8X1 + 10X2 + 12X3 + 12X4 + 7X5 + 18X6 + 20X7 + 14X8≤ 51,408
