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Tresset [83]
3 years ago
8

Please help me answer this question I will be given the brainliest as well

Physics
1 answer:
Sophie [7]3 years ago
3 0

draw a horizontal straight line from 25 to 75 and connects the line drawn at 75 to the bottom of the graph (0) at 90 with a straight line

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The ossicles (the three tiny bones in the middle ear) are responsible for __________.
Feliz [49]

Answer:

D.amplifying sound vibrations from the eardrum

this is correct

3 0
3 years ago
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a mass of 10kg is placed on a horizontal table with coefficient of friction is 0.5. if the mass is static, determine weight of t
zloy xaker [14]

Answer:

10

Explanation:

5 0
3 years ago
NEED NOW ALMOST DUE
Arte-miy333 [17]

Answer:

Asteroids are objects made of clay and silicate  that orbit the sun but are too small to be considered planets.

Most asteroids revolve around the sun in an orbit between those of Mars and Jupiter.

They form a wide band called the Asteroid belt.

Other asteroids have orbits that cross Earth’s orbit. These asteroids are called  Earth-crossers.

Asteroids probably consist of matter that never agglomerated into a planet when the solar system was forming.

The comet’s core is composed of ice and dust.

Comets heat up and begin to change from a solid to a gas as they approach the sun.

The matter surrounding a comet’s core is vaporized and forms a very bright halo of ice or dust not sure, and an enormous cloud of dust or gasses not sure envelopes the head of the comet.

7 0
3 years ago
The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a
s344n2d4d5 [400]

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = 0.85\times 1.989\times 10^{30}\ kg=1.69065\times 10^{30}\ kg

r = Radius of orbit of planet = 0.11\times 149.6\times 10^{9}\ m=16.456\times 10^{9}\ m

v = Orbital speed

The kinetic and potential energy balance is given by

\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\dfrac{Gm}{r}}\\\Rightarrow v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.69065\times 10^{30}}{16.456\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

t=\frac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi \times 16.456\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\dfrac{1249040.48419}{24\times 60\times 60}=14.45\ days  

The orbital period is 14.45 days

5 0
2 years ago
If predators are increased, then the cricket frog population will (increase/decrease/stay the same) over the span of five years.
12345 [234]
With an increase of predators, then the population will most likely decrease over the span of 5 years.
4 0
3 years ago
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