Answer:
The shape of a bird's beak is a clue to its main source of food. The shape of a bird's beak is designed for eating particular types of food such as: seeds, fruit, insects, nectar, fish, or small mammals. Bird beaks have adapted over time to help birds find food within their habitat which allows them to survive. The beak, bill, and/or rostrum is an external anatomical structure found mostly in birds, but also in non-avian dinosaurs and some mammals. A beak is used for eating and for preening, manipulating objects, killing prey, fighting, probing for food, courtship and feeding young.
The options are missing and they are;
A) the electric force increases because the balloon loses its charge.
B) the electric force increases because the distance increases.
C) the electric force decreases because the distance increases.
D) the electric force decreases because his hair loses its charge.
Answer:
Correct answer is option C - the electric force decreases because the distance increases.
Explanation:
The formula for electric force is;
F = k•q1•q2/r²
Where;
K is coulombs constant
q1 and q2 are particle charges
r is distance
So,looking at the formula given earlier, if we increase the distance, the denominator will increase and thus the Force will decrease.
So the correct option is option C
Answer:
air or vacuum is the least refractive index medium of most rare medium
all other medium has more value of refractive index and hence the speed will be less than the speed of the air
Explanation:
As we know that speed of light in any medium and speed of light in air is related to each other by the equation
here we know that
[tex]\mu [tex] = refractive index of the medium
so we know that air or vacuum is the least refractive index medium of most rare medium
all other medium has more value of refractive index and hence the speed will be less than the speed of the air
Answer:
V = 3.6 volts
Explanation:
From Ohm's Law, we know that:
V = IR
but,
R = ρL/A
Therefore,
V = IρL/A
where,
V = Potential Difference = ?
I = Current = 4 A
ρ = resistivity of copper = 1.68 x 10⁻⁸ Ω.m
L = Length = 70 m
A = Cross-sectional Area = πd²/4 = π(1.29 x 10⁻³ m)²/4 [16 gauge wire has a diameter of 1.29 mm]
A = 1.31 x 10⁻⁶ m²
V = (4 A)(1.68 x 10⁻⁸ Ω.m)(70 m)/(1.31 x 10⁻⁶ m²)
<u>V = 3.6 volts</u>
